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Updated: Aug 26, 2026

Functional Reconstitution and Channel Activity Measurements of Purified Wildtype and Mutant CFTR Protein
Published on: March 9, 2015
General anesthetic octanol and related compounds activate wild-type and delF508 cystic fibrosis chloride channels
Brice Marcet1, Frédéric Becq, Caroline Norez
1Institut de Neurosciences Physiologiques et Cognitives, INPC-CNRS, 31 Chemin Joseph Aiguier, 13402 Marseille, Cedex 20, France. marcet@dpm.cnrs-mrs.fr
Abstract:
1. Cystic fibrosis transmembrane conductance regulator (CFTR) Cl(-) channel is defective during cystic fibrosis (CF). Activators of the CFTR Cl(-) channel may be useful for therapy of CF. Here, we demonstrate that a range of general anesthetics like normal-alkanols (n-alkanols) and related compounds can stimulate the Cl(-) channel activity of wild-type CFTR and delF508-CFTR mutant. 2. The effects of n-alkanols like octanol on CFTR activity were measured by iodide ((125)I) efflux and patch-clamp techniques on three distinct cellular models: (1). CFTR-expressing Chinese hamster ovary cells, (2). human airway Calu-3 epithelial cells and (3). human airway JME/CF15 epithelial cells which express the delF508-CFTR mutant. 3. Our data show for the first time that n-alkanols activate both wild-type CFTR and delF508-CFTR mutant. Octanol stimulated (125)I efflux in a dose-dependent manner in CFTR-expressing cells (wild-type and delF508) but not in cell lines lacking CFTR. (125)I efflux and Cl(-) currents induced by octanol were blocked by glibenclamide but insensitive to 4,4'-diisothiocyanatostilbene-2,2'-disulfonic acid, as expected for a CFTR Cl(-) current. 4. CFTR activation by octanol was neither due to cell-to-cell uncoupling properties of octanol nor to an intracellular cAMP increase. CFTR activation by octanol requires phosphorylation by protein kinase-A (PKA) since it was prevented by H-89, a PKA inhibitor. 5. n-Alkanols chain length was an important determinant for channel activation, with rank order of potencies: 1-heptanol<1-octanol<2-octanol<1-decanol. Our findings may be of valuable interest for developing novel therapeutic strategies for CF.
Insights
General anesthetics like n-alkanols can activate the cystic fibrosis transmembrane conductance regulator (CFTR) Cl(-) channel, including the delF508-CFTR mutant. This finding offers potential for new cystic fibrosis (CF) therapies.
Area of Science:
- Biochemistry
- Molecular Biology
- Pharmacology
Background:
- Cystic fibrosis (CF) is characterized by a defective cystic fibrosis transmembrane conductance regulator (CFTR) Cl(-) channel.
- Activating the CFTR Cl(-) channel presents a potential therapeutic strategy for CF.
Purpose of the Study:
- To investigate the potential of general anesthetics, specifically n-alkanols, as activators of both wild-type and mutant CFTR Cl(-) channels.
- To explore the mechanism by which n-alkanols modulate CFTR activity.
Main Methods:
- Utilized iodide ((125)I) efflux assays and patch-clamp electrophysiology.
- Employed three distinct cellular models: CFTR-expressing Chinese hamster ovary cells, Calu-3 epithelial cells, and JME/CF15 epithelial cells (delF508-CFTR mutant).
Main Results:
- Demonstrated that n-alkanols, including octanol, activate both wild-type and delF508-CFTR channels in a dose-dependent manner.
- Confirmed that octanol-induced activation is specific to CFTR, as it was observed in CFTR-expressing cells but not in control cells.
- Showed that octanol-induced CFTR activation requires protein kinase-A (PKA) phosphorylation and is blocked by glibenclamide.
Conclusions:
- n-Alkanols are novel activators of the CFTR Cl(-) channel, effective against both wild-type and the common delF508-CFTR mutation.
- The findings suggest that n-alkanols and related compounds could be valuable in developing new therapeutic approaches for cystic fibrosis.
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