Synthesis, crystal structure and molecular conformation of N-Ac-dehydro-Phe-L-Val-OH

The peptide N-Ac-dehydro-Phe-L-Val-OH (C16H20N2O4) was synthesized by the usual workup procedure. The peptide crystallizes from its solution in acetonitrile at 4 degrees in hexagonal space group P6(5) with a = b = 11.874(2)A, c = 21.856(9) A, V = 2668(1) A3, Z = 6, dm = 1.151(3) g cm-3, dc = 1.136(4) g cm-3, CuK alpha = 1.5418 A, mu = 0.641 mm-1, F(000) = 972, T = 293 K. The structure was solved by direct methods and refined by least-squares procedure to an R value of 0.074 for 1922 observed reflections. In the dehydro-residue, the C1 alpha-C1 beta distance is 1.35(1) A while the bond angle C1 alpha-C1 beta-C1 gamma is 131.2(9) degrees. The backbone torsion angles are: omega 0 = 172(1) degrees, phi 1 = -60(2) degrees, psi 1 = -31(2) degrees, omega 1 = -179(1) degrees, phi 2 = 59(2) degrees. These values suggest that the peptide tends to adopt an alternating right-handed and left-handed helical conformation. The side chain torsion angles are: chi 1(1) = -6(2) degrees, chi 1(2.1) = -1(2) degrees, chi 1(2.2) = -178(2) degrees, chi 2(1.1) = 63(2) degrees and chi 2(1.2) = -173(1) degrees. These values show that the side chain of dehydro-Phe is planar whereas the valyl side chain adopts a sterically most preferred conformation. The molecules, linked by intermolecular hydrogen bonds and van der Waals forces, are arranged in helices along the c-axis. The helices are held side-by-side by van der Waals contacts.