Related Experiment Video
Updated: Jun 1, 2026

Microwave-Assisted Preparation of 1-Aryl-1H-pyrazole-5-amines
Published on: June 23, 2019
5-Chloro-N-[2-(1H-imidazol-4-yl)eth-yl]-N-methyl-7H-pyrrolo[2,3-d]pyrimidin-4-amine
Abstract:
The title compound, C(12)H(13)ClN(6), was prepared by reaction of 4,5-dichloro-7H-pyrrolo[2,3-d]pyrimidine with 2-(1H-imid-azol-4-yl)-N-methyl-ethanamine, and the X-ray study confirmed that chloro-substituent in six-membered ring was replaced in the reaction. The exocyclic N atom environment is approximately coplanar with the pyrrolo[2,3-d]pyrimidine [corresponding dihedral angle is 5.5 (1)°], whereas the mean plane of the N-C-C-C link connecting with the imidazolyl ring is almost exactly orthogonal to the plane of the bicyclic system [dihedral angle = 91.6 (2)°]. The imidazolyl plane itself, however, forms a relatively small dihedral angle of 20.8 (1)° with the pyrrolo[2,3-d]pyrimidine plane. There are two independent N-H⋯N hydrogen bonds in the structure, which link mol-ecules into layers parallel to (03).
More Related Videos
Related Concept Videos
Nomenclature of Aryl and Heterocyclic Amines
Basicity of Heterocyclic Aromatic Amines
Preparation of 1° Amines: Hofmann and Curtius Rearrangement Overview
Physical Properties of Amines
Adrenergic Agonists: Chemistry and Structure-Activity Relationship
Aromatic ring substitutions: Substituting the aromatic ring with –OH groups at positions 3 and 4 yields catecholamines (e.g., epinephrine), which have a high affinity for adrenoceptors. Hydrogen bonding between –OH groups and receptors enhances adrenergic activity.
Separation of the aromatic...
Five-Membered Heterocyclic Aromatic Compounds: Overview

