Comparative evolutionary genomics of medaka and three-spined stickleback fabp2a and fabp2b genes with fabp2 of...

Here we describe the evolutionary relationship of the duplicated intestinal fatty acid binding protein genes fabp2a and fabp2b from medaka and three-spined stickleback by comparing them to the well-studied fabp2 gene from zebrafish. The duplicated fabp2 genes from medaka and three-spined stickleback consist of four exons separated by three introns, which code for a polypeptide of 132 amino acids. Fabp2a and Fabp2b of medaka and three-spined stickleback share highest sequence identity with zebrafish Fabp2. All Fabp2/FABP2 sequences from vertebrates form a distinct clade in a neighbor-joining phylogenetic tree with a robust 100% bootstrap value, which indicates that the medaka and three-spined stickleback fabp2a and fabp2b are orthologs of zebrafish fabp2. The syntenic genes of fabp2a and fabp2b from medaka and three-spined stickleback were shown to be conserved with the syntenic genes of fabp2/FABP2 from zebrafish and human, evidence that the duplicated fabp2 genes from medaka and three-spined stickleback most likely arose from the teleost-specific whole-genome duplication. The tissue-specific distribution of medaka and three-spined stickleback fabp2a and fabp2b transcripts, and zebrafish fabp2 transcripts, assayed by RT-qPCR suggests the acquisition of new function(s) by the medaka fabp2a, and the distinct evolution of fabp2b compared with fabp2a in the medaka and three-spined stickleback genomes.