A highly crystalline single Au wire network as a high temperature transparent heater
K D M Rao1, Giridhar U Kulkarni
1Chemistry & Physics of Materials Unit and Thematic Unit of Excellence in Nanochemistry, Jawaharlal Nehru Centre for Advanced Scientific Research, Jakkur P.O., Bangalore 560064, India. kulkarni@jncasr.ac.in.
Nanoscale
|April 24, 2014
Summary
Researchers developed a transparent gold (Au) wire network on quartz that functions as a high-temperature heater. This novel transparent conductor reaches ~600°C quickly and shows improved performance after self-annealing via joule heating.
Area of Science:
- Materials Science
- Optoelectronics
- Nanotechnology
Background:
- Transparent conductors are crucial for optoelectronic devices.
- High-temperature transparent heaters are needed for advanced applications.
- Existing materials often face limitations in performance or stability.
Purpose of the Study:
- To develop a novel transparent conductor capable of generating high temperatures.
- To investigate the fabrication and performance of a gold (Au) wire network on quartz as a transparent heater.
- To evaluate the thermal stability and optical/electrical properties of the fabricated heater.
Main Methods:
- Fabrication of a gold (Au) wire network using a cracked sacrificial template.
- Characterization of optical transmittance and sheet resistance.
- Joule heating experiments to determine temperature generation capabilities.
- Analysis of structural changes (crystallinity) and property improvements after annealing.
Main Results:
- A highly interconnected Au wire network on quartz was successfully fabricated.
- The network exhibited high transmittance (~87%) and low sheet resistance (5.4 Ω □(-1)).
- The transparent heater reached temperatures of ~600°C rapidly via joule heating.
- Self-annealing through joule heating improved crystallinity, transmittance (to 92%), and reduced sheet resistance (to 3.2 Ω □(-1)).
Conclusions:
- The Au wire network on quartz is an effective high-temperature transparent heater.
- Seamless junctions in the network contribute to its thermal performance and stability.
- Joule heating-induced self-annealing enhances the material's properties, offering a pathway for further optimization.
Related Concept Videos
Thermal expansion and Thermal stress: Problem Solving
2.2K
San Francisco's Golden Gate Bridge is exposed to temperatures ranging from -15 °C to 40 °C. At its coldest, the main span of the bridge is 1275 m long. Assuming that the bridge is made entirely of steel, what is the change in its length between these temperatures?
To solve the problem, first, identify the known and unknown quantities. The initial length (L) of the bridge is 1275 m, the coefficient of linear expansion (α) for steel is 12 x 10-6/°C, and the change in temperature (ΔT) is 55...
To solve the problem, first, identify the known and unknown quantities. The initial length (L) of the bridge is 1275 m, the coefficient of linear expansion (α) for steel is 12 x 10-6/°C, and the change in temperature (ΔT) is 55...
2.2K
Network Covalent Solids
12.9K
Network covalent solids contain a three-dimensional network of covalently bonded atoms as found in the crystal structures of nonmetals like diamond, graphite, silicon, and some covalent compounds, such as silicon dioxide (sand) and silicon carbide (carborundum, the abrasive on sandpaper). Many minerals have networks of covalent bonds.
To break or to melt a covalent network solid, covalent bonds must be broken. Because covalent bonds are relatively strong, covalent network solids are typically...
To break or to melt a covalent network solid, covalent bonds must be broken. Because covalent bonds are relatively strong, covalent network solids are typically...
12.9K
Magnetic Field Due To A Thin Straight Wire
5.1K
Consider an infinitely long straight wire carrying a current I. The magnetic field at point P at a distance a from the origin can be calculated using the Biot-Savart law.
5.1K
Magnetic Field Due to Two Straight Wires
5.2K
Consider two parallel straight wires carrying a current of 10 A and 20 A in the same direction and separated by a distance of 20 cm. Calculate the magnetic field at a point "P2", midway between the wires. Also, evaluate the magnetic field when the direction of the current is reversed in the second wire.
5.2K


