APC ((Cdc20) 通过破坏 Pds1 亚纳相抑制剂和环素 Clb5 的作用来促进脱离线粒分裂的过程
M Shirayama1, A Tóth, M Gálová
1Research Institute of Molecular Pathology, Vienna, Austria.
Nature
|January 26, 2000
概括
亚纳酶促进复合体/循环体 (APC/C) 控制细胞分裂. 在酵母中,APC/C针对Pds1降解释放Cdc14,这对于线粒细胞退出和细胞增殖至关重要.
科学领域:
- 细胞生物学 细胞生物学
- 分子生物学分子生物学
- 生物化学 生物化学
背景情况:
- 通过亚纳促进复合体/循环体 (APC/C) 的乌比奎丁介导蛋白解对细胞循环进展至关重要.
- 由Cdc20和Cdh1/Hct1等子单元调节的APC/C活动驱动着姐妹染色体的分离和线粒体的退出.
- Cdc14酸酶对于线粒体退出至关重要,涉及Cdh1激活和Sic1积累,但其释放机制尚不清楚.
研究的目的:
- 阐明Cdc20 (APC(Cdc20)) 结合的APC/C在激活Cdc14酸酶中的作用.
- 研究APC(Cdc20) 介导的蛋白质分解如何在Saccharomyces cerevisiae中促进线粒体退出和细胞增殖.
- 确定APC的特定基质 (Cdc20),这些基质对于Cdc14激活和随后的细胞周期事件至关重要.
主要方法:
- 在Saccharomyces cerevisiae中利用了酵母遗传学.
- 研究的蛋白质降解途径由阿纳酶促进复合体/循环体 (APC/C) 介导.
- 分析了Pds1,Clb5,Cdc14,Cdc20,Cdh1和Sic1在线粒分裂中的作用.
主要成果:
- APC(Cdc20) 调解了Pds1和S相环林Clb5.5的降解.
- 为了从核中释放Cdc14酸酶,需要Pds1降解.
- 对于Cdc14来说,Clb5降解是必不可少的,可以使Cdk1失活,并激活Cdh1和Sic1,从而促进线粒体的退出.
- 缺乏Pds1和Clb5的细胞可以在没有Cdc20的情况下繁殖.
结论:
- APC ((Cdc20) 在通过降解Pds1和Clb5.5来促进线粒体的退出方面发挥着双重作用.
- 通过APC的Pds1降解 (Cdc20) 是Cdc14释放的先决条件,而Clb5降解对于Cdc14的下游功能至关重要.
- 这些发现揭示了线粒体退出的关键调节机制,并突出了在特定突变背景下APC/C功能的冗余性.
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