弹道量子电线的四端电阻
R de Picciotto1, H L Stormer, L N Pfeiffer
1Bell-Labs, Lucent Technologies, Murray Hill, New Jersey 07974, USA. rd25@lucent.com
Nature
|May 3, 2001
概括
研究人员观察到弹道量子电线中的电阻消失,这挑战了标准的两探头测量. 这一发现凸显了散射在电阻现象中的重要性.
科学领域:
- 凝聚物质物理学 凝聚物质物理学
- 量子运输是一种量子运输.
背景情况:
- 电阻源于电荷载体运动量因散射而放松.
- 在没有散射的完美导体中,电阻在理论上为零.
研究的目的:
- 为了研究单模弹道量子电线中的电阻.
- 为了比较四个终端的电阻测量与标准的两探头测量.
主要方法:
- 用于控制几何结构的GaAs/AlGaAs异构结构的裂边上利用表轴生长.
- 在弹道量子电线上使用弱入侵的电压探测器.
主要成果:
- 在弹道量子电线中观察到四个终端电阻的消失.
- 与标准的两探头电阻值约为13kΩ (h/2e2) 相比.
结论:
- 在弹道运输条件下,在干净的,一维的导体中展示了消失阻力.
- 这项研究提供了实验证据,证明当分散被最小化时,阻力不存在.
相关概念视频
Magnetic Field Due to Two Straight Wires
5.4K
Consider two parallel straight wires carrying a current of 10 A and 20 A in the same direction and separated by a distance of 20 cm. Calculate the magnetic field at a point "P2", midway between the wires. Also, evaluate the magnetic field when the direction of the current is reversed in the second wire.
5.4K
Resistance
7.7K
When a current moves through any conductor, the conductor causes some level of difficulty for the current to flow. The measure of that difficulty is known as the resistance of the material and is represented by R. Every material has its own resistance. In the case of conductors, heat is emitted whenever a current passes through them. Resistance depends on the resistivity of the material. Resistivity is a characteristic of the material used to fabricate electrical components, whereas the...
7.7K
Magnetic Field Due To A Thin Straight Wire
6.7K
Consider an infinitely long straight wire carrying a current I. The magnetic field at point P at a distance a from the origin can be calculated using the Biot-Savart law.
6.7K
Magnetic Force On Current-Carrying Wires: Example
2.4K
In a magnetic field, moving charges encounter a force. If a wire contains these moving charges, i.e., if the wire is carrying a current, then a force acts on the wire as well. Consider a pair of flexible leads holding a wire that is 40 cm long and 10 g in weight in a horizontal position. The wire is placed in a constant magnetic field of 0.40 T, as shown in Figure 1(a). Determine the magnitude and direction of the current flowing in the wire needed to remove the tension in the supporting leads.
2.4K
Equivalent Resistance
1.2K
In circuit analysis, situations often arise where resistors are neither in series nor parallel configurations. To tackle such scenarios, three-terminal equivalent networks like the wye (Y) (Figure 1 (a)) or tee (T) and delta (Δ) (Figure 1 (b)) or pi (π) networks come into play. These networks offer versatile solutions and are frequently encountered in various applications, including three-phase electrical systems, electrical filters, and matching networks.
1.2K
Thevinin's Theorem
1.9K
Thévenin's theorem plays a pivotal role in electrical circuit analysis, offering a solution to the challenges posed by variable loads within a circuit. In practical applications, it is common to encounter circuits where certain elements remain fixed while others fluctuate, often referred to as the "load." A typical household electrical outlet serves as a prime example of a variable load, as it can be connected to a variety of appliances, each with its own unique electrical characteristics.
1.9K


