安基林的纳米弹行为重复
Gwangrog Lee1, Khadar Abdi, Yong Jiang
1Department of Mechanical Engineering and Materials Science and Center for Biologically Inspired Materials and Material Systems, Duke University, Durham, North Carolina 27708, USA.
Nature
|January 18, 2006
概括
安基林重复,常见的蛋白质图案,充当弹性弹. 展开的重复也可以在重新折叠时产生力,揭示机械传导和纳米设备的新特性.
科学领域:
- 生物物理学的生物物理.
- 分子生物学分子生物学
- 材料科学 材料科学 材料科学
背景情况:
- 安基林重复是参与分子识别的无处不在的蛋白质动机.
- 这些重复形成超螺旋结构,其潜在的弹状特性在机械感受器中被认为是.
- 暂时受体潜力 (TRP) 通道中的安基林重复堆与关闭机械敏感通道有关.
研究的目的:
- 为了研究合脚重复的机械性质.
- 为了确定ankyrin重复结构是否表现出弹性和类似弹的行为.
- 为了测量在ankyrin重复折叠时产生的力.
主要方法:
- 使用原子力显微镜 (AFM) 的单分子力谱学.
- 测量以三级结构为基础的合脚回复的弹性.
- 在蛋白质重新折叠过程中产生的力量的量化.
主要成果:
- 协奏式脚的重复表现出基于三级结构的弹性,表现为线性和完全可逆的弹.
- 展开的基林重复表现出一种意想不到的能力,在重新折叠时产生力量.
- 蛋白质域的重新折叠力首次直接测量.
结论:
- 由于其三级结构,安基林重复物具有固有的弹状特性.
- 在ankyrin重复的重新折叠过程中产生的力是一个新的发现.
- 这些弹特性对机械传导机制和新型纳米设备的开发有影响.
相关概念视频
Nuclear Stability
20.5K
Protons and neutrons, collectively called nucleons, are packed together tightly in a nucleus. With a radius of about 10−15 meters, a nucleus is quite small compared to the radius of the entire atom, which is about 10−10 meters. Nuclei are extremely dense compared to bulk matter, averaging 1.8 × 1014 grams per cubic centimeter. If the earth’s density were equal to the average nuclear density, the earth’s radius would be only about 200 meters.
To hold positively...
To hold positively...
20.5K
Atomic Nuclei: Nuclear Spin
5.1K
All atomic particles possess an intrinsic angular momentum, or 'spin'. Electrons, protons, and neutrons each have a spin value of ½, although protons and neutrons in nuclei may have higher half-integer spins owing to energetic factors.
Atomic nuclei have a net nuclear spin, , which can have an integer or half-integer value. In atomic nuclei, the spins of protons are paired against each other but not with neutrons, and vice versa. Consequently, an even number of protons does not contribute...
Atomic nuclei have a net nuclear spin, , which can have an integer or half-integer value. In atomic nuclei, the spins of protons are paired against each other but not with neutrons, and vice versa. Consequently, an even number of protons does not contribute...
5.1K


