在染色质上SIRT1的再分配促进了基因组的稳定性,但在衰老过程中改变了基因表达
Philipp Oberdoerffer1, Shaday Michan, Michael McVay
1Department of Pathology and Glenn Labs for Aging Research, Harvard Medical School, Boston, MA 02115, USA.
Cell
|December 2, 2008
概括
哺乳动物SIRT1,一个Sir2同类,通过抑制重复的DNA和基因来维护基因组稳定性. DNA损伤触发SIRT1转移到修复部位,减轻与年龄相关的基因表达变化并促进生存.
科学领域:
- 分子生物学分子生物学
- 遗传学 是一个遗传学.
- 衰老研究研究 衰老研究
背景情况:
- 基因组不稳定性和基因表达的改变是衰老的关键特征.
- 酵母Sir2沉默基因并稳定DNA,但在衰老过程中其转移会导致基因沉默和不育.
- Sir2的哺乳动物同类是SIRT1,这是一个参与各种细胞过程的蛋白质.
研究的目的:
- 研究哺乳动物SIRT1在维持基因组稳定性及其在衰老过程中的功能中的作用.
- 为了确定SIRT1在对DNA损伤的反应中表现的行为是否与酵母 Sir2的行为相似.
- 评估SIRT1表达增加对生存率和年龄相关的转录变化的影响.
主要方法:
- 利用小鼠胚胎干细胞研究SIRT1功能.
- 检查了SIRT1与重复性DNA和基因位置的相互作用.
- 研究SIRT1的局部化,以应对DNA损伤.
- 在基因组不稳定的小鼠模型中评估SIRT1表达增加的影响.
主要成果:
- 哺乳动物SIRT1抑制了重复的DNA和老鼠基因组中的多种基因组.
- 在DNA受损时,SIRT1与其目标位点分离,并迁移到DNA断裂,促进修复.
- 这种转移会导致类似于老老鼠大脑中观察到的转录变化.
- 增加SIRT1表达增加了基因组不稳定模型中的生存率,并抑制了与年龄相关的基因表达变化.
结论:
- SIRT1在抑制潜在有害的DNA元素和调节基因表达方面发挥着至关重要的作用.
- 由于DNA损伤引起的SIRT1再分配是一种保存机制,促进了基因组稳定性,并可能减缓衰老.
- 在DNA修复和基因调节中的SIRT1的功能突显了它在真核生物的衰老过程中的重要性.
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