金属-布伦斯特酸合作催化用于不对称的还原性氨基化
Chaoqun Li1, Barbara Villa-Marcos, Jianliang Xiao
1Liverpool Centre for Materials and Catalysis, Department of Chemistry, University of Liverpool, Liverpool L69 7ZD, UK.
Journal of the American Chemical Society
|May 1, 2009
概括
通过合作催化实现了子的直接还原性氨基化. 一个 ((III) - 胺复合物和酸使这种高效的化学转化成为可能.
科学领域:
- 有机化学 有机化学
- 催化剂是一种催化剂.
- 不对称的合成方法
背景情况:
- 还原性氨化是有机合成中形成碳键的关键反应.
- 开发高效的催化系统,用于直接减少胺的氨化仍然是一个重大挑战.
研究的目的:
- 开发一种新型的催化系统,用于对广泛的子进行直接还原性氨化.
- 在还原性氨化过程中实现高效率和选择性.
主要方法:
- 使用一种合作催化方法,涉及 (III) - 胺复合物.
- 采用奇拉酸或其基作为联合催化剂.
主要成果:
- 成功地证明了广泛的类素的直接还原性氨基化.
- 合作催化系统在转化过程中被证明是有效的.
结论:
- 开发的Ir(III) - 胺和酸合作催化系统是直接降解氨基化的强大工具.
- 这种方法提供了一条有效的途径,以获得有价值的氨基化合物.
相关概念视频
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The metal catalyst used can be either heterogeneous or homogeneous. When hydrogenation of an alkene generates a chiral center, a pair of enantiomeric products is expected to form. However, an enantiomeric excess of one of the products can be facilitated using an enantioselective reaction or an...
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Amide reduction with strong reducing agents like lithium aluminum hydride proceeds through a nucleophilic acyl substitution to form amines. Primary, secondary, and tertiary amides yield primary, secondary, and tertiary amines, respectively.
Amide reduction requires two equivalents of the reducing agent, acting as a source of hydride ions. As shown in the figure, the reaction is initiated with a nucleophilic attack by the hydride ion at the carbonyl carbon to form a tetrahedral intermediate.
Amide reduction requires two equivalents of the reducing agent, acting as a source of hydride ions. As shown in the figure, the reaction is initiated with a nucleophilic attack by the hydride ion at the carbonyl carbon to form a tetrahedral intermediate.
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Various carboxylic acid derivatives (such as acid chlorides, esters, and anhydrides) can be used for the acylation of amines to yield amides. The reaction requires two equivalents of amines. The first amine molecule functions as a nucleophile and attacks the carbonyl carbon to produce a tetrahedral intermediate. This is followed by the loss of the leaving group and restoration of the C=O bond.
Next, the second equivalent of amine serves as a Brønsted base and deprotonates the quaternary amide...
Next, the second equivalent of amine serves as a Brønsted base and deprotonates the quaternary amide...


