使用SmI(2) 和H(2) O2进行乳降解的机制,选择性和合成实用性的研究
Dixit Parmar1, Lorna A Duffy, Dhandapani V Sadasivam
1School of Chemistry, University of Manchester, Oxford Road, Manchester, M13 9PL, United Kingdom.
用水激活的三二化物 (SmI(2) 现在可以减少简单的和乳. 这种新型的SmI(2) -H(2) O系统可以选择性地减少六个成员的乳,并使二分体选择性循环.
科学领域:
- 有机化学 有机化学
- 合成化学 合成化学
- 兰化物化学 兰化物化学
背景情况:
- 和乳以前被认为是对二氧化 (SmI(2) 的还原具有抗性.
- 新的激活方法对于扩大类试剂的合成效用至关重要.
研究的目的:
- 为了研究用水激活的SmI(2) 来减少和乳.
- 探索这种新的减少系统的选择性和机制性途径.
- 为了利用生成的基质中间体用于随后的合成转化.
主要方法:
- 使用可控量的水 (H) 激活SmI2O.
- 停止流的光谱光度测量用于动力学研究.
- 实验和计算分析以阐明反应机制.
- 激进循环化反应形成循环或.
主要成果:
- SmI(2)-H(2)O系统有效地减少了简单的阿里法和乳.
- 观察到完全的选择性减少六个成员的乳比其他乳和.
- 激素中间体在循环化反应中得到了成功的应用,产生了具有高 diastereoselectivity 的循环产物.
- 这些循环反应代表了使用碳酸作为乙烯基基相当的基循环的第一个实例.
结论:
- 水的激活释放了SmI的降解力(2) 对于和乳.
- SmI(2)-H(2)O系统提供了一种选择性和强大的乳降低方法.
- 这种方法为通过基-基基循环的循环化合物的二元选择性合成提供了一条新的途径.
更多相关视频
07:36Versatile CO2 Transformations into Complex Products: A One-pot Two-step Strategy
Published on: November 9, 2019
06:31Highly Stereoselective Synthesis of 1,6-Ketoesters Mediated by Ionic Liquids: A Three-component Reaction Enabling Rapid Access to a New Class of Low Molecular Weight Gelators
Published on: November 27, 2015
相关概念视频
Alcohols from Carbonyl Compounds: Reduction
Catalytic hydrogenation is similar to the reduction of an alkene or alkyne by adding H2 across the pi bond in the presence of transition metal catalysts like Raney Ni, Pd–C, Pt, or Ru. Aldehydes and ketones can be reduced by this method, often under mild to moderate heat (25–100°C) and...
Acid Halides to Alcohols: LiAlH4 Reduction
The mechanism proceeds in three steps. First, the nucleophilic hydride ion attacks the carbonyl carbon of the acid halide to form a tetrahedral intermediate. Next, the carbonyl group is re-formed, and the halide ion departs as a leaving group, generating an aldehyde. A second nucleophilic attack by the hydride yields an alkoxide ion, which, upon protonation, gives a primary alcohol as...
Amides to Amines: LiAlH4 Reduction
Amide reduction requires two equivalents of the reducing agent, acting as a source of hydride ions. As shown in the figure, the reaction is initiated with a nucleophilic attack by the hydride ion at the carbonyl carbon to form a tetrahedral intermediate.
Nitriles to Amines: LiAlH4 Reduction
As shown below, the mechanism involves three steps. Firstly, the hydride ion acting as a nucleophile attacks the nitrile carbon to form an anion. In the second step, a second equivalent of the hydride ion attacks the anion to...
Esters to Alcohols: Hydride Reductions
Lithium aluminum hydride is a source of hydride ions and functions as a nucleophile. The mechanism proceeds in three steps. Firstly, the nucleophilic hydride ion attacks the carbonyl carbon of the ester to form a tetrahedral intermediate. Subsequently, the carbonyl group re-forms,...
Reduction of Alkenes: Asymmetric Catalytic Hydrogenation
The metal catalyst used can be either heterogeneous or homogeneous. When hydrogenation of an alkene generates a chiral center, a pair of enantiomeric products is expected to form. However, an enantiomeric excess of one of the products can be facilitated using an enantioselective reaction or an...
