在H3S10ph和H4K16ac之间的基因组交叉生成一个基因组代码,该代码介导转录延长
Alessio Zippo1, Riccardo Serafini, Marina Rocchigiani
1Dipartimento di Biologia Molecolare Università di Siena, Siena, Italy.
Cell
|September 22, 2009
概括
在10 (H3S10ph) 处的基因组H3酸化启动了一连串激活FOSL1基因转录的过程. 这涉及PIM1激酶,14-3-3,MOF和BRD4,导致增强的RNA聚合酶II过程性.
科学领域:
- 分子生物学分子生物学
- 表观遗传学 在表观遗传学中,表观遗传学是指表观遗传学.
- 基因规则 基因规则
背景情况:
- 质子修饰,如酸化和乙化,在调节基因转录中起着至关重要的作用.
- 在10 (H3S10ph) 基素H3的酸化与转录激活有关,但精确的分子机制仍然不完全理解.
研究的目的:
- 阐明H3S10ph触发FOSL1基因的转录延长的分子机制.
- 为了确定参与这种信号级联的关键蛋白质和基因素修饰.
主要方法:
- 研究了PIM1激酶在FOSL1增强器中的酸化组素H3中的作用.
- 利用共免疫沉和生化分析来确定14-3-3,MOF和BRD4之间的相互作用.
- 分析了组蛋白修饰 (H3S10ph,H4K16ac) 以及它们对使用染色体免疫沉和RNA测序对转录延长的影响.
主要成果:
- 血清刺激激活PIM1激酶以在FOSL1增强剂中酸化预乙基化组素H3.
- 适应蛋白14-3-3结合H3S10ph核细胞,并招募基因组酸转移酶MOF,导致H4K16ac.
- 这种基因组交叉创建一个H3K9acS10ph/H4K16ac代码,招募BRD4和随后的P-TEFb,它释放暂停的RNA聚合酶II以增强延长.
结论:
- H3S10ph作为FOSL1基因转录延长的关键触发剂.
- 一个涉及PIM1,14-3-3,MOF和BRD4的顺序级联介导H3S10ph诱导的转录.
- 这项研究揭示了一种新的核细胞识别代码 (H3K9acS10ph/H4K16ac),对于招募转录延长因子至关重要.
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Histone Modification
The histone proteins have a flexible N-terminal tail extending out from the nucleosome. These histone tails are often subjected to post-translational modifications such as acetylation, methylation, phosphorylation, and ubiquitination. Particular combinations of these modifications form “histone codes” that influence the chromatin folding and tissue-specific gene expression.
Acetylation
The enzyme histone acetyltransferase adds acetyl group to the histones. Another enzyme, histone deacetylase,...
Acetylation
The enzyme histone acetyltransferase adds acetyl group to the histones. Another enzyme, histone deacetylase,...
The Nucleosome Core Particle
Nucleosomes are the DNA-histone complex, where the DNA strand is wound around the histone core. The histone core is an octamer containing two copies of H2A, H2B, H3, and H4 histone proteins.
Nucleosomes, paradoxically, perform two opposite functions simultaneously. On the one hand, their primary aim is to protect the delicate DNA strands from physical damage and help achieve a higher compaction ratio. On the other hand, they must allow polymerase enzymes to access histone-bound DNA during...
Nucleosomes, paradoxically, perform two opposite functions simultaneously. On the one hand, their primary aim is to protect the delicate DNA strands from physical damage and help achieve a higher compaction ratio. On the other hand, they must allow polymerase enzymes to access histone-bound DNA during...
