从 ((t) Bu2bpy) Pd(Me) 2:(IV) 中的氧化诱导的还原性消除:在一个电子氧化反应中的中间体
Michael P Lanci1, Matthew S Remy, Werner Kaminsky
1Department of Chemistry, University of Washington, Box 351700, Seattle, Washington 98195-1700, USA.
Journal of the American Chemical Society
|October 15, 2009
概括
这项研究探讨了复合物如何通过氧化形成碳-碳键. 不同的氧化剂显示出不同的反应途径,涉及中间体,影响C-C键形成机制.
科学领域:
- 有机金属化学 有机金属化学
- 催化剂是一种催化剂.
- 反应机制 反应机制
背景情况:
- 复合物在催化过程中至关重要.
- 了解氧化C-C键的形成是合成效率的关键.
- 从Pd(II) 前体中减少性消除的机制需要进一步阐明.
研究的目的:
- 为了研究一种特定的复合物中氧化诱导的C-C键形成的还原性消除的机制.
- 为了比较反应路径与不同的外层氧化剂.
- 为了确定所涉及的中间体的氧化状态.
主要方法:
- 通过使用各种氧化剂,研究了从 ((t) Bu (((2) bpy) Pd ((II) (((Me) ((2) 中的还原性消除.
- 分析反应产品和中间体.
- 通过动力学和光谱学研究探测了机械路径.
主要成果:
- 铁氧化剂表明一种涉及Pd(III) 和Pd(IV) 中间体的机制,由Pd(IV) 形成C-C键.
- Ag(+) 氧化剂通过Pd-Ag(+) adduct和内部球电子转移到Pd(III).
- 二氧化剂通过一个不同的途径产生乙,而没有甲基混杂,产生Pd(0) 产品.
结论:
- 形成C-C键的反应途径是氧化剂依赖的.
- 可能涉及多个氧化状态 (Pd(0),Pd(II),Pd(III),Pd(IV).
- 截然不同的机制决定了从复合体中减少性消除的结果.
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