控制铜复合体对二氧化碳的催化两电子相比四电子还原的因素
Shunichi Fukuzumi1, Laleh Tahsini, Yong-Min Lee
1Department of Bioinspired Science, Ewha Womans University, Seoul 120-750, Korea. fukuzumi@chem.eng.osaka-u.ac.jp
Journal of the American Chemical Society
|April 3, 2012
概括
一个双核铜复合体有效地催化氧的两电子减小,使用十甲基铁作为减小剂. 这个过程涉及质子化和电子转移步骤,最终产生过氧化并再生催化剂.
科学领域:
- 协调化学 协调化学
- 催化剂是一种催化剂.
- 生物有机化学 生物有机化学
背景情况:
- 减少氧气在生物系统和催化过程中至关重要.
- 铁衍生物是有效的单电子减电剂.
- 双核铜复合体可以模仿酶活性位点.
研究的目的:
- 为了研究双核Cu (II) 复合物的催化机制,以减少氧气.
- 阐明三酸在催化循环中的作用.
- 识别反应中间体和反应途径.
主要方法:
- 在低温下进行光谱分析 (UV-Vis).
- 电子转移反应的动力学研究.
- 铜复合物的电化学表征.
主要成果:
- 双核Cu (II) 复合体, [Cu (II) 2 (LO) 2 (OH) 2+) ],在三酸 (HOTF) 的存在下,催化O (O2) 的二电子还原由十甲基烯 (Fc*) 催化.
- 通过HOTF对复合物的质子化促进了Fc*的减少,通过两步电子转移机制进行.
- 低温研究确定了多 ([Cu(II) ) 和水 ([Cu(II) ) 的中间体.
- 催化循环产生H(2) O(2) 并再生活性催化剂, [Cu(II) ((2) ((LO) ((OTF) ] ((2+).
- 动力分析揭示了两种不同的反应途径,涉及电子转移到混合价值二铜 (II) 中介物.
结论:
- 双核铜复合物有效地催化了O(2) 减少到H(2) O(2) 使用Fc*作为减少剂.
- 三酸在激活催化剂和促进反应方面发挥着关键作用.
- 该研究提供了对铜复合体减少氧气的机制的见解,这与生物无机化学和催化有关.
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