双重复制基因的协同调节减缓了哺乳动物的亚功能化演变
Xun Lan1, Jonathan K Pritchard2
1Department of Genetics, Stanford University, Stanford, CA, USA. Howard Hughes Medical Institute, Stanford University, Stanford, CA, USA. xlan@stanford.edu pritch@stanford.edu.
概括
基因复制是基因组进化的关键. 大多数新的复制品都会丢失,但剂量共享有助于哺乳动物的基因拷贝最初存活下来,其次是功能适应速度较慢.
科学领域:
- 进化生物学
- 基因组学
- 分子生物学
背景情况:
- 基因复制是基因组进化的主要驱动力.
- 基因复制物的长期存活是有争议的,其中包括子/新功能化和剂量共享的模型.
- 大多数年轻的复制品由于功能丧失的突变而丢失.
研究的目的:
- 研究使哺乳动物长期保留基因复制物的进化机制.
- 区分子功能化和剂量共享作为重复基因存活的主要驱动因素.
主要方法:
- 分析了46个人类和26个小鼠组织的RNA测序数据.
- 对年轻复制基因的基因表达模式进行比较分析.
- 审查监管要素及其在共同监管中的潜在作用.
主要成果:
- 基因表达的亚功能化发展缓慢,在胎盘哺乳动物复制体中并不常见.
- 双重复制似乎是由共享的基因组元素共同调节的,这可能会阻碍独立进化.
- 大多数年轻复制品表现出下调的表达, 匹配单复制基因水平, 支持剂量共享.
结论:
- 分享剂量表达是哺乳动物复制基因最初存活的关键机制.
- 较慢的功能适应,如亚功能化,在最初的生存后促进长期的保存.
- 这些发现挑战了早期复制保留中的子功能化的优势,并强调了剂量效应的作用.
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