SmI2(H2O)n 通过质子合电子转移减少富含电子的胺
Scott S Kolmar1, James M Mayer1
1Department of Chemistry, Yale University , New Haven, Connecticut 06520, United States.
Journal of the American Chemical Society
|July 19, 2017
概括
二氧化物 (SmI2) 与水一起作为一种强大的减少剂,通过协同的质子合电子转移途径有效地减少酶. 这表明SmI2 ((H2O) n是强原子的供体,能够形成非常弱的C-H键.
科学领域:
- 有机化学
- 减氧化学
- 试剂开发
背景情况:
- 二氧化物 (SmI2) 是一种多用途的还原剂,主要用于碳化合物.
- 最近的研究强调了水中的SmI2和THF (SmI2(H2O) 作为一种有用的试剂.
- 胺是富含电子的基质,具有独特的还原挑战.
研究的目的:
- 通过使用SmI2(H2O) n来研究胺的减少.
- 阐明反应机制,区分各种电子和质子转移途径.
- 评估SmI2(H2O) n的原子捐赠能力.
主要方法:
- 使用SmI2(H2O) n进行胺的实验降解.
- 机械研究包括对初始外层电子转移,质子转移或基质协调的证据.
- 热化学分析以确定结合解离的自由能量 (BDFEs).
主要成果:
- SmI2 ((H2O) n有效地降低了胺.
- 机械实验强烈支持协同的质子合电子转移 (PCET) 途径.
- 形成的 C-H 键的 BDFE 值为 ~32 kcal mol-1,而水离子的 O-H BDFE 值为 ~26 kcal mol-1.
- 这些值表明SmI2(H2O) n是一个非常强的原子供体.
结论:
- SmI2 ((H2O) n是一种强大的电子丰富基质的还原剂,如胺.
- 而不是简单的外层电子转移或质子转移.
- 试剂形成非常弱的C-H键的能力强调了其作为原子供体的强度.
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