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相关概念视频

Rigid Body Equilibrium Problems - I00:49

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A rigid body is said to be in static equilibrium when the net force and the net torque acting on the system is equal to zero. To solve for rigid body equilibrium problems, do the following steps.
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Shear Diagram01:27

Shear Diagram

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In the study of beam mechanics, shear diagrams play a crucial role in understanding the distribution of shear forces along the length of a beam. Consider a beam AB that is supported at both ends and subjected to perpendicular loads.
First, a free-body diagram of the beam is drawn, representing all the external forces and internal reactions acting on the beam. One can calculate the reaction forces at each support by employing the equilibrium equations of force and moment. The vertical component...
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Shearing Stress01:19

Shearing Stress

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Shearing stress, denoted by the Greek letter tau (τ), is stress caused by forces acting transversely on an object. These forces create internal ones within the entity in the plane where the external forces are applied. The resultant of these internal forces is the shear in the section.
The average shearing stress can be calculated by dividing the shear by the area of the cross-section.
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Shearing Strain01:20

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The shearing strain represents a cubic element's angular change when subjected to shearing stress. This type of stress can transform a cube into an oblique parallelepiped without influencing normal strains. The cubic element experiences a significant transformation when exposed solely to shearing stress. Its shape alters from a perfect cube into a rhomboid, clearly demonstrating the effect of shearing strain. The degree of this strain is considered positive if it reduces the angle between the...
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Rigid Body Equilibrium Problems - II01:21

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A rigid body is in static equilibrium when the net force and the net torque acting on the system are equal to zero.
Consider two children sitting on a seesaw, which has negligible mass. The first child has a mass (m1) of 26 kg and sits at point A, which is 1.6 meters (r1) from the pivot point B; the second child has a mass (m2) of 32 kg and sits at point C. How far from the pivot point B should the second child sit (r2) to balance the seesaw?
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Angular Momentum: Rigid Body01:11

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The total angular momentum of a rigid body can be calculated using the summation of the angular momentum of all the tiny particles rotating in the same plane. Considering all the tiny particles rotating in the x-y plane, the direction of angular momentum of all such particles and that of the rigid body would be perpendicular to the plane of the rotation along the z-axis.
This calculation can get complicated when tiny particles within the rigid body are not rotating in the same plane but have...
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在剪切辅助学中使用手工制造会产生硬且符合要求的结构.

Jeffrey Ian Lipton1, Robert MacCurdy2, Zachary Manchester3

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概括

在大自然的启发下, 这些新材料可以是合规的或是刚性的,在机器人,医学和工程领域都有应用.

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The Assembly and Application of 'Shear Rings': A Novel Endothelial Model for Orbital, Unidirectional and Periodic Fluid Flow and Shear Stress
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科学领域:

  • 材料科学
  • 机械学
  • 几何学

背景情况:

  • 自然利用重复的单元来创造复杂的手工结构,
  • 具有负波桑比率的辅性材料在张力下膨胀,并由重复的单元细胞构成.
  • 在辅助结构中实现手性是个挑战,限制了它们的设计复杂性和应用.

研究的目的:

  • 开发一种在扩张过程中表现出剪切变形的辅助性单元中引入手性的方法.
  • 探索设计规则,规范辅助式的对称性和对齐,以控制手性.
  • 为了展示手工剪切辅助材料的制造,能够各种表面并形成复合结构.

主要方法:

  • 对称性和对齐原理在辅助中进行了研究,以诱导手性.
  • 开发了制造手动辅助单元细胞的规则,这些单元细胞在紧张时会剪切.
  • 应用这些规则来设计平面,圆柱形和球形几何体的辅助体.
  • 复合手工剪裁辅助剂, 模仿天然材料如质蛋白和原蛋白.

主要成果:

  • 成功产生了可控制的手性和剪切行为的辅助性单元细胞.
  • 证明了这些手持辅助器的复杂表面 (平面,圆柱体,球体) 的能力.
  • 创建具有可调节性质的复合结构,从符合规范的扭曲材料到刚性锁定可部署系统.

结论:

  • 开发的对称性和对齐规则使得创建新型手动剪切辅助材料成为可能.
  • 这些材料提供了前所未有的机械反应控制,包括合规性和刚性.
  • 这些发现为设计用于化学框架,医疗设备,机器人和可部署结构的先进材料开辟了新的途径.