在Ca9中Mn2+的发光-MnNa (PO4) 固体溶液中Mn7的发光,0≤x≤1
Eldar M Gallyamov1, Vladimir V Titkov1, Vladimir N Lebedev1
1Department of Chemistry, Lomonosov Moscow State University, 119991 Moscow, Russia.
Materials (Basel, Switzerland)
|June 28, 2023
概括
这项研究合成了新型的Mn2+化,Ca9Zn1-xMnxNa,PO47,呈现出红色发射. 合成方法简单而坚固,产生可调节发光强度的光体.
科学领域:
- 材料科学 材料科学 材料科学
- 固态化学 固态化学
- 发光的光度是非常的低.
背景情况:
- 为可见光应用开发高效的光剂至关重要.
- 在酸盐宿主中 (Mn2+) 兴奋剂提供了红色发射材料的潜力.
- 控制的合成是实现所需的发光性能和避免火的关键.
研究的目的:
- 为了合成和描述一种新的系列的Mn2+化,Ca9Zn1-xMnxNaPO4) 7化.
- 研究这些光体的结构和发光特性.
- 了解兴奋剂度和发光行为之间的关系.
主要方法:
- 在还原大气下使用活性炭进行固体相反应.
- 粉末X射线衍射 (PXRD) 用于结构分析.
- 光学第二和生成测量.
- 发光光谱学用于分析辐射光谱和强度.
主要成果:
- 固体溶液Ca9Zn1-xMnxNa(PO4) 7成功合成,结晶成非中心对称β-Ca3(PO4) 2类型结构 (空间组R3c).
- 在406nm激发下观察到以650nm为中心的宽红色发射带,归因于Mn2+的4T1 →6A1过渡.
- 发光强度在Mn2+度 (x) 上线增加至0.5,在较高的兴奋剂水平 (x=0.7) 上观察到度灭.
- PXRD和瑞特维尔德精细化证实,Mn2+和Zn2+离子在M5八面体位点替代Ca2+.
结论:
- 建立了一种简单而强大的合成Mn2+化的方法.
- 合成的Ca9Zn1-xMnxNa(PO4) 7体显示出由于Mn2+的兴奋剂而有希望的红色发光.
- 发光特性取决于Mn2+度,有可能调节度火开始时低于度火的发射强度.
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