双性FBXW7淘汰诱导AKAP8介导的DNA损伤邻近的野生型细胞
Dedrick Kok Hong Chan1,2, Amit Mandal1, Svenja Hester3
1Nuffield Department of Surgical Sciences, University of Oxford, Oxford, UK.
Cell death discovery
|June 29, 2023
概括
结直肠癌细胞中的FBXW7突变会通过分泌的AKAP8在邻近细胞中引起DNA损伤. 这突显了亚克隆相互作用对瘤发展的影响.
科学领域:
- 在瘤学瘤学.
- 分子生物学分子生物学
- 癌症遗传学 癌症遗传学
背景情况:
- 大肠直肠癌表现出显著的内异质性.
- 驱动突变之间的亚克隆相互作用至关重要,但尚未完全理解.
- FBXW7是结直肠癌中经常发生突变的驱动基因.
研究的目的:
- 研究FBXW7突变对结直肠癌细胞行为和克隆间相互作用的影响.
- 确定FBXW7突变细胞影响邻近野生类型细胞的机制.
主要方法:
- 使用CRISPR-Cas9.9生成的同源FBXW7突变结直肠癌细胞.
- 利用Transwell共同培养系统研究细胞与细胞的相互作用.
- 采用质谱法来识别分泌的因素.
- 评估了DNA损伤和扩散率.
主要成果:
- FBXW7突变细胞显示氧化酸化和DNA损伤增加,但增殖减少.
- 与FBXW7突变细胞共培养的野生型细胞显示出DNA损伤,与与野生型细胞共培养的细胞不同.
- FBXW7突变细胞分泌AKAP8,从而诱导野生细胞的DNA损伤.
- 在突变细胞中删除AKAP8在共同培养的野生类型细胞中废除了DNA损伤表型.
结论:
- FBXW7突变结肠直肠癌细胞通过AKAP8分泌诱导邻近的野生类型细胞中的DNA损伤.
- 这种由AKAP8介导的细胞间通信代表了结直肠癌进展的新机制.
- 了解这些亚克隆相互作用对于向癌症治疗至关重要.
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