一个假设测试,用于检测区域数据中的特定距离聚类和分散.
Stella Self1, Anna Overby2, Anja Zgodic1
1Arnold School of Public Health, University of South Carolina, 921 Assembly Street, Columbia, SC 29208, USA.
概括
本研究引入了正面面积比例函数 (PAPF) 来检测面积数据中的空间聚类,为分析地理模式提供了一种新方法. PAPF方法在现实世界的应用中显示出希望,例如保护和公共卫生分析.
科学领域:
- 空间统计的空间统计.
- 地理信息系统 (GIS) 是指地理信息系统.
- 环境科学环境科学
背景情况:
- 空间聚类检测在各种领域至关重要,从流行病学到神经科学.
- 里普利的K函数是点过程数据的标准,但对面积数据不太适应.
- 准确评估面积数据中的空间模式仍然是一个挑战.
研究的目的:
- 开发一种用于检测面积数据中的空间聚类和分散的新方法.
- 引入受瑞普利K函数启发的正面面积比例函数 (PAPF).
- 根据现有的空间统计数据,评估PAPF假设测试的性能.
主要方法:
- 用于面积数据分析的正面面积比例函数 (PAPF) 的开发.
- 创建一个基于PAPF的假设测试程序.
- 通过模拟,比较PAPF测试与全球Moran's I,Getis-Ord G和空间扫描统计数据.
- 对土地块和县级健康数据的现实应用.
主要成果:
- PAPF提供了一种新的方法,用于在面积数据中检测空间聚类.
- 模拟研究证明了PAPF测试的性能.
- 现实世界的分析成功地确定了空间聚类在保护服务和儿科超重/肥胖率.
结论:
- 积极面积比例函数 (PAPF) 为面积数据的空间聚类分析提供了一个有价值的工具.
- PAPF假设测试是特定空间分析现有方法的可行替代方案.
- 这种方法对于理解不同领域的地理分布具有实际意义.
相关概念视频
Test for Homogeneity
2.0K
The goodness–of–fit test can be used to decide whether a population fits a given distribution, but it will not suffice to decide whether two populations follow the same unknown distribution. A different test, called the test for homogeneity, can be used to conclude whether two populations have the same distribution. To calculate the test statistic for a test for homogeneity, follow the same procedure as with the test of independence. The hypotheses for the test for homogeneity can...
2.0K
One-Way ANOVA: Unequal Sample Sizes
5.8K
One-way ANOVA can be performed on three or more samples of unequal sizes. However, calculations get complicated when sample sizes are not always the same. So, while performing ANOVA with unequal samples size, the following equation is used:
5.8K
One-Way ANOVA: Equal Sample Sizes
3.3K
One-Way ANOVA can be performed on three or more samples with equal or unequal sample sizes. When one-way ANOVA is performed on two datasets with samples of equal sizes, it can be easily observed that the computed F statistic is highly sensitive to the sample mean.
Different sample means can result in different values for the variance estimate: variance between samples. This is because the variance between samples is calculated as the product of the sample size and the variance between the...
Different sample means can result in different values for the variance estimate: variance between samples. This is because the variance between samples is calculated as the product of the sample size and the variance between the...
3.3K
Kruskal-Wallis Test
819
The Kruskal-Wallis test, also known as the Kruskal-Wallis H test, serves as a nonparametric alternative to the one-way ANOVA, offering a solution for analyzing the differences across three or more independent groups based on a single, ordinal-dependent variable. This statistical test is particularly valuable in scenarios where the data does not meet the normal distribution assumption required by its parametric counterparts. Kruskal-Wallis test is designed typically to handle ordinal data or...
819
Statistical Hypothesis Testing
2.0K
Hypothesis testing is a critical statistical procedure facilitating informed, evidence-based decisions. It begins with a hypothesis, which is a tentative explanation, or a prediction about a population parameter. This hypothesis can be either a null hypothesis (H0), indicating no effect or difference, or an alternative hypothesis (Ha), suggesting an effect or difference.
Statistical significance measures the probability that an observed result occurred by chance. If this probability, known as...
Statistical significance measures the probability that an observed result occurred by chance. If this probability, known as...
2.0K
Hypothesis Test for Test of Independence
3.6K
The test of independence is a chi-square-based test used to determine whether two variables or factors are independent or dependent. This hypothesis test is used to examine the independence of the variables. One can construct two qualitative survey questions or experiments based on the variables in a contingency table. The goal is to see if the two variables are unrelated (independent) or related (dependent). The null and alternative hypotheses for this test are:
H0: The two variables (factors)...
H0: The two variables (factors)...
3.6K


