基于线性损伤进化定律的新数值方法用于预测TiB的机械性质2/6061AlAl
Weigang Fu1, Junchi Ma1, Zhe Liao1
1Aviation Engineering Institute, Civil Aviation Flight University of China, Guanghan 618330, China.
Materials (Basel, Switzerland)
|July 14, 2023
概括
添加二氧化 (TiB2) 颗粒可以提高6061 (Al) 复合材料的强度,但可以减少延长. 颗粒聚类对性和延长有负面影响,突出显示了颗粒分布的重要性.
科学领域:
- 材料科学 材料科学 材料科学
- 机械工程 机械工程
- 复合材料 复合材料 复合材料
背景情况:
- 二化物 (TiB2) 颗粒用于加强6061 (Al) 金属矩阵复合材料.
- 了解这些复合材料的机械性能对于它们的应用至关重要.
研究的目的:
- 研究TiB2颗粒含量和聚类对TiB2/6061Al复合材料机械性能的影响.
- 建立一个复合行为的预测模型.
主要方法:
- 基于SEM图像建立的TiB2/6061Al复合材料的3D代表体积元素 (RVE).
- 嵌入的柔性矩阵损伤和接口行为与线性损伤进化.
- 在混合边界条件下进行RVE拉伸实验.
主要成果:
- 增加的TiB2含量 (重量2.5%至12.5%) 提高了弹性模量,屈服强度和拉伸强度,分别为8%,10.37%和11.55%.
- 随着TiB2含量增加,延长率下降了10%.
- 较高的TiB2颗粒聚合 (20%至80%) 并没有提高承载能力,并减少了8%的延伸.
结论:
- TiB2颗粒增加了承载能力,但降低了6061Al复合材料的柔性.
- 粒子聚类显著影响性和延伸,更高的聚类导致延伸减少.
- 粒子间距对于管理应力场和裂传播至关重要.
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