相关实验视频
Updated: Jul 15, 2025

14:23
Design and Optimization Strategies of a High-Performance Vented Box
Published on: June 9, 2023
1.2K
立方体的链袖的多目标优化设计基于Kriging的设计
Xuan Sun1,2,3, Ting Liu1,2,3, Jiguang Jia1,2,3
1School of Mechanic and Control Engineering, Guilin University of Technology Guilin, Guilin, China.
Science progress
|September 27, 2023
概括
这项研究优化了Hinge Sleeve of Cubic (HSC) 设计,通过综合方法将其质量减少了24.84%. 这种轻量级的设计满足了生产需求,降低了成本,并促进了材料的使用.
科学领域:
- 机械工程 机械工程
- 计算工程 计算工程
- 材料科学 材料科学 材料科学
背景情况:
- 立方体 (HSC) 的套需要优化以提高性能和效率.
- 轻量化设计对于降低材料成本和提高机械元件的可用性至关重要.
研究的目的:
- 为了实现立方体 (HSC) 的链袖的多目标最佳设计.
- 为了减少HSC的质量,同时保持性能和满足生产要求.
主要方法:
- 结合中央复合设计 (CCD),Kriging建模和多目标遗传算法 (MOGA).
- 建立了HSC模型,选择了设计变量,并确定了关键的几何约束.
- 利用Kriging进行响应表面建模和MOGA进行优化.
主要成果:
- 优化HSC模型实现了24.84%的质量减少.
- 优化策略在轻量化设计中被证明是可靠的.
- 节省了设计成本,提高了材料利用率.
结论:
- 集成优化方法对于设计像HSC这样的机械元件是有效的.
- 在不影响生产标准的情况下,实现了HSC的显著轻量化.
- 该研究展示了一种可行的方法,用于具有成本效益和材料效率的组件设计.
相关概念视频
Design of Prismatic Beams for Bending
257
The design of prismatic beams, structural elements with a uniform cross-section, focuses on ensuring safety and structural integrity under load. The design process begins by determining the allowable stress, either from material properties tables, or by dividing the material's ultimate strength by a safety factor. This safety factor is essential for accommodating uncertainties, and varies depending on the material—timber, steel, or concrete—with each having unique strength and...
257
Generalized Hooke's Law
1.0K
The generalized Hooke's Law is a broadened version of Hooke's Law, which extends to all types of stress and in every direction. Consider an isotropic material shaped into a cube subjected to multiaxial loading. In this scenario, normal stresses are exerted along the three coordinate axes. As a result of these stresses, the cubic shape deforms into a rectangular parallelepiped. Despite this deformation, the new shape maintains equal sides, and there is a normal strain in the direction of the...
1.0K
Unsymmetric Loading of Thin-Walled Members: Problem Solving
125
The shear center of a channel section with uniform thickness, height, and width, is determined by computing the shear force in the member and calculating the moments of inertia of the sections.
To compute the shear forces, find the shear flow at a specific distance from the endpoint using the vertical shear and the moment of inertia values. The total shear force on the flange is calculated by integrating the shear flow from one end of the flange to the other.
Next, calculate the moments of...
To compute the shear forces, find the shear flow at a specific distance from the endpoint using the vertical shear and the moment of inertia values. The total shear force on the flange is calculated by integrating the shear flow from one end of the flange to the other.
Next, calculate the moments of...
125
Method of Joints: Problem Solving II
606
Consider a truss structure with frictionless joints fixed to a wall and roller support. If a force of 150 N is applied to joint A, the forces in each member of the truss can be determined using the method of joints.
606
Design of Transmission Shafts - Stress Analysis
393
Designing a transmission shaft requires a thorough understanding of the stresses induced by bending moments and torques, especially in systems where power is transferred through gears. These forces create force-couple systems at the centers of the shaft's cross-sections, leading to both transverse and torsional loading. Although shearing stresses from transverse loads are typically smaller than those from torques and are often overlooked, the significant normal stresses from these loads...
393
Internal Loadings in Structural Members: Problem Solving
1.3K
When designing or analyzing a structural member, it is important to consider the internal loadings developed within the member. These internal loadings include normal force, shear force, and bending moment. Engineers can ensure that the structural member can support the applied external forces by calculating these internal loadings.
To illustrate this, let's consider a beam OC of 5 kN, inclined at an angle of 53.13° with the horizontal and supported at both ends. Determine the internal...
To illustrate this, let's consider a beam OC of 5 kN, inclined at an angle of 53.13° with the horizontal and supported at both ends. Determine the internal...
1.3K

