杆断裂和剪切应力之间的相关性:一个新的参数
Seth Street1, Abhijith V Matur1, Xu Tao1
1Department of Neurosurgery, University of Cincinnati College of Medicine, Cincinnati, Ohio, USA.
World neurosurgery
|December 21, 2023
概括
一个新的杆切割应力 (RSS) 参数在预测成年脊柱形手术后的杆骨折 (RF) 风险方面表现有希望. 虽然仪器级别的数量也是一个强有力的预测指标,但RSS可能会提供更个性化的风险评估.
科学领域:
- 整形外科手术 整形外科手术
- 生物机械工程 生物机械工程
- 脊柱融合研究研究 脊柱融合研究
背景情况:
- 成年脊柱形纠正通常涉及脊柱仪器仪器.
- 杆骨折 (RF) 是脊髓融合手术后的潜在并发症.
- 准确识别患有射频风险的患者对于手术规划和患者的结果至关重要.
研究的目的:
- 评估新型杆切削应力 (RSS) 参数在预测射频风险方面的准确性.
- 将RSS的预测精度与其组成变量进行比较,特别是仪器级别的数量.
主要方法:
- 成年脊柱形患者 (≥18岁) 的回顾性综述,随访时间≥24个月.
- 计算RSS参数 (RSS=Nwd2) 使用患者体重 (w),仪器水平数量 (N) 和最小杆径 (d).
- 使用接收器运行特征 (ROC) 曲线来确定曲线下的面积 (AUC),灵敏度,特异性和概率比率 (LRs) 的分析.
主要成果:
- RSS参数显示了最高的分辨准确度,AUC为0.73 (±0.11).
- 在30.1的截止值下,RSS获得了71.4%的灵敏度和71.4%的特异性 (LR,2.5).
- 仪表水平的数量与射频有很强的相关性,其AUC为0.65 (±0.12).
结论:
- 从易于获得的数据中获得的RSS参数显示,在脊髓融合后预测患者特定的射频风险具有潜力.
- 仪器级别的数量也是射频的重要预测指标,并没有比RSS少得多.
- 建议使用更大的样本大小进行进一步的前性研究,以确定RSS或RF预测的其他参数的优越性.
相关概念视频
Stresses in a Shaft
378
The shaft PQ is subjected to a twisting force when equal and opposite torques are applied on either side. A section that cuts perpendicular to the shaft's axis at any arbitrary point R is examined to understand this. When the free-body diagram of the QR segment is analyzed, it reveals the shearing forces exerted by the PR portion onto the QR segment as the shaft experiences twisting.
Applying equilibrium conditions to the QR segment establishes that the internal shearing forces within the...
Applying equilibrium conditions to the QR segment establishes that the internal shearing forces within the...
378
Temperature Dependent Deformation
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In a nonhomogeneous rod made up of steel and brass, restrained at both ends and subjected to a temperature change, several steps are involved in calculating the stress and compressive load. Due to the problem's static indeterminacy, one end support is disconnected, allowing the rod to experience the temperature change freely. Next, an unknown force is applied at the free end, triggering deformations in the rod's steel and brass portions. These deformations are then calculated and added...
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Relation between Poisson's ratio, Modulus of Elasticity and Modulus of Rigidity
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Deformation occurs in axial and transverse directions when an axial load is applied to a slender bar. This deformation impacts the cubic element within the bar, transforming it into either a rectangular parallelepiped or a rhombus, contingent on its orientation. This transformation process induces shearing strain. Axial loading elicits both shearing and normal strains. Applying an axial load instigates equal normal and shearing stresses on elements oriented at a 45° angle to the load axis.
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Plastic Deformation in Circular Shafts
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When materials are subjected to forces that surpass their yield strength, they undergo a process known as plastic deformation. This results in a permanent alteration or strain in their structure. This concept can be specifically applied to circular shafts, where the deformation leads to a change in its shape. The precise evaluation of this plastic deformation requires understanding the stress distribution within the circular shaft, which is achieved by calculating the maximum shearing stress in...
190
Shearing Stress
572
Shearing stress, denoted by the Greek letter tau (τ), is stress caused by forces acting transversely on an object. These forces create internal ones within the entity in the plane where the external forces are applied. The resultant of these internal forces is the shear in the section.
The average shearing stress can be calculated by dividing the shear by the area of the cross-section.
The average shearing stress can be calculated by dividing the shear by the area of the cross-section.
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Circular Shaft - Stresses in Linear Range
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Consider a scenario where a circular shaft is subject to torque that remains within the boundaries of Hooke's Law, avoiding any permanent deformation. So, the formula for shearing strain is revisited. This formula is multiplied by the modulus of rigidity, and then Hooke's Law for the shearing stress and strain is applied. As a result, the equation for shearing stress in a shaft can be derived.
245


