在垂直轴冲击粉碎机内的碰撞能量分析基于计算流体动力学-离散元件方法
Canhui Wu1, Limei Zhao1, Zhen Cao1
1School of Mechanical Engineering, Guizhou University, Guiyang 550025, China.
ACS omega
|February 26, 2024
概括
本研究使用气体固体合模型来分析冲击粉碎机中的粒子碰撞. 提高破碎机速度可以提高材料破碎效率,降低能源消耗.
科学领域:
- 机械工程 机械工程
- 材料科学 材料科学 材料科学
- 计算流体动力学的流体动力学.
背景情况:
- 垂直轴冲击破碎机中的粒子碰撞对于材料破碎和能量消耗至关重要.
- 了解碰撞能量分布是优化粉碎机效率和能源消耗的关键.
研究的目的:
- 调查VSI粉碎机中的粒子碰撞能量,频率和能量光谱的区域分布.
- 为垂直轴冲击粉碎机的节能设计提供理论基础.
主要方法:
- 一个计算流体动力学 (CFD) 和离散元素方法 (DEM) 合模型被开发来模拟气体-固体相互作用.
- 使用PL8500 VSI破碎机进行实验验证,并将模拟结果与经验数据进行比较.
主要成果:
- 流体-固体合模型准确地预测了粉碎室内的碰撞能量分布.
- 较高的旋转速度增加了碰撞频率和能量,促进了材料的破裂.
- 增加料速率对断裂速率的影响最小,但减少了整体系统的特定能量.
结论:
- 该CFD-DEM模型为VSI破碎机中的粒子碰撞动态提供了可靠的预测.
- 优化旋转速度是提高断裂效率和能源管理的有效方法.
- 这些发现支持开发更高效,更节能的粉碎机设计.
相关概念视频
Thin-Walled Hollow Shafts
189
In analyzing a thin-walled hollow shaft subjected to torsional loading, a segment with width dx is isolated for examination. Despite its equilibrium state, this segment faces torsional shearing forces at its ends. These forces are quantitatively described by the product of the longitudinal shearing stress on the segment's minor surface and the area of this surface, leading to the concept of shear flow. This shear flow is consistent throughout the structure, indicating a uniform distribution...
189
Impact
146
Impact occurs when two bodies collide, leading to the application of impulsive forces between them. Analyzing impact mechanics involves considering two colliding particles moving along a line known as the line of impact, which passes through their centers and is perpendicular to the contact plane.
When particles with different initial velocities collide, they induce deformation by applying equal and opposite impulses. At the point of maximum deformation, the particles move together with...
When particles with different initial velocities collide, they induce deformation by applying equal and opposite impulses. At the point of maximum deformation, the particles move together with...
146
Collisions in Multiple Dimensions: Problem Solving
4.2K
In multiple dimensions, the conservation of momentum applies in each direction independently. Hence, to solve collisions in multiple dimensions, we should write down the momentum conservation in each direction separately. To help understand collisions in multiple dimensions, consider an example.
A small car of mass 1,200 kg traveling east at 60 km/h collides at an intersection with a truck of mass 3,000 kg traveling due north at 40 km/h. The two vehicles are locked together. What is the...
A small car of mass 1,200 kg traveling east at 60 km/h collides at an intersection with a truck of mass 3,000 kg traveling due north at 40 km/h. The two vehicles are locked together. What is the...
4.2K
Conservation of Energy in Control Volume
837
Consider a turbine operating under steady-flow conditions. The control volume is drawn around the turbine, with fluid entering at one point and exiting at another. The turbine extracts energy from the fluid, which performs mechanical work (shaft work).
For steady flow systems, the time derivative of the stored energy becomes zero since there is no energy accumulation within the control volume. This simplifies the energy equation to:
For steady flow systems, the time derivative of the stored energy becomes zero since there is no energy accumulation within the control volume. This simplifies the energy equation to:
837
Design of Transmission Shafts - Stress Analysis
357
Designing a transmission shaft requires a thorough understanding of the stresses induced by bending moments and torques, especially in systems where power is transferred through gears. These forces create force-couple systems at the centers of the shaft's cross-sections, leading to both transverse and torsional loading. Although shearing stresses from transverse loads are typically smaller than those from torques and are often overlooked, the significant normal stresses from these loads...
357
Shear on the Horizontal Face of a Beam Element
173
To understand shear on the flat side of a prismatic beam element, consider the vertical and horizontal shearing forces, and the normal forces, acting on the element. The element's upper (U) and lower (L) sections, which are divided by the beam's neutral axis, are examined. The equilibrium of these forces is determined by applying the equilibrium equation, which helps identify the horizontal shearing force. This force is directly related to the bending moments and the cross-section's...
173


