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相关概念视频

Coplanar Forces01:25

Coplanar Forces

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Consider an object upon which multiple forces are acting. If the lines of action of each force lie within the same plane, the system can be considered coplanar. The Cartesian vector form can be used to resolve each force into its respective components. For a coplanar system, the system will be in equilibrium if each component of the resultant force equals zero and the resultant force on the system is zero. If the sum of the forces is not equal to zero, then the object will not be in equilibrium...
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Gauss's Law: Cylindrical Symmetry01:20

Gauss's Law: Cylindrical Symmetry

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A charge distribution has cylindrical symmetry if the charge density depends only upon the distance from the axis of the cylinder and does not vary along the axis or with the direction about the axis. In other words, if a system varies if it is rotated around the axis or shifted along the axis, it does not have cylindrical symmetry. In real systems, we do not have infinite cylinders; however, if the cylindrical object is considerably longer than the radius from it that we are interested in,...
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Mohr's Circle for Moments of Inertia: Problem Solving01:14

Mohr's Circle for Moments of Inertia: Problem Solving

2.0K
Mohr's circle is a graphical method for determining an area's principal moments by plotting the moments and product of inertia on a rectangular coordinate system. This circle can also be used to calculate the orientation of the principal axes.
Consider a rectangular beam. The moments of inertia of the beam about the x and y axis are 2.5(107) mm4 and 7.5(107) mm4, respectively. The product of inertia is 1.5(107) mm4. Determine the principal moments of inertia and the orientation of the major and...
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Dynamics Of Circular Motion: Applications01:17

Dynamics Of Circular Motion: Applications

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Suppose a car moves on flat ground and turns to the left. The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. For this, a minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway. Let's now consider banked curves, where the slope of the road helps in negotiating the curve. The greater the angle of the curve, the faster one can take the curve. It is common for race tracks for...
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Perpendicular-Axis Theorem01:16

Perpendicular-Axis Theorem

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The perpendicular-axis theorem states that the moment of inertia of a planar object about an axis perpendicular to its plane is equal to the sum of the moments of inertia about two mutually perpendicular concurrent axes lying in the plane of the body.
Consider a circular disc of mass M and radius R lying along an x-y plane. The origin lies at the center of the disc, and the z-axis is perpendicular to the disc's plane. All three axes coincide at the disc's center. The moment of inertia of this...
2.8K
Gauss's Law: Planar Symmetry01:27

Gauss's Law: Planar Symmetry

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A planar symmetry of charge density is obtained when charges are uniformly spread over a large flat surface. In planar symmetry, all points in a plane parallel to the plane of charge are identical with respect to the charges. Suppose the plane of the charge distribution is the xy-plane, and the electric field at a space point P with coordinates (x, y, z) is to be determined. Since the charge density is the same at all (x, y) - coordinates in the z = 0 plane, by symmetry, the electric field at P...
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相关实验视频

Updated: Jun 29, 2025

Kinematic History of a Salient-recess Junction Explored through a Combined Approach of Field Data and Analog Sandbox Modeling
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经典力学可以感知形交叉吗?

Sourav Karmakar1, Saumya Thakur1, Amber Jain1

  • 1Department of Chemistry, Indian Institute of Technology Bombay, Bombay, India.

The Journal of chemical physics
|March 25, 2024
PubMed
概括

缓慢振动模式的激发是能量放松的关键,这种现象与振动形交叉点 (CI) 相关. 量子经典和经典模拟都显示了这种快速的能量转移,证实了CICI.

科学领域:

  • 物理化学 物理化学
  • 化学物理 化学物理
  • 量子动力学 量子动力学是什么?

背景情况:

  • 已知状交叉点 (CI) 可以促进快速的电子能量传输.
  • 之前的工作确立了振动形交叉点 (CI) 的存在及其在振动能量放松中的作用.

研究的目的:

  • 在模型系统中研究振动能量放松的机制.
  • 探索振动模式时间尺度在能量放松中的作用.
  • 用混合量子-经典和经典方法分析系统.

主要方法:

  • 利用一个孤立的模型哈密尔顿系统,具有四种振动模式 (两个快,两个慢).
  • 采用混合量子-经典的表面跳跃模拟.
  • 进行了完全经典的模拟.

主要成果:

  • 证明缓慢振动模式的激发对能量放松机制至关重要.
  • 在表面跳跃和经典模拟中观察到快速能量放松.
  • 确定了快速能量放松作为形交叉 (CI) 存在的签名.

结论:

  • 振动形交叉点显著影响振动能量放松动态.

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  • 缓慢的振动模式在促进快速能量消散方面发挥着至关重要的作用.
  • 经典和混合量子-经典模拟可以捕获形交叉点的签名.