无形和纳米晶体软磁材料在平衡力类型电磁继电器中的应用
Ding Ding1, Jiaxin You1, Xiangqian Cui1
1Institute of Reliability in Electrical Apparatus and Electronics, Harbin Institute of Technology, Harbin 150001, China.
Micromachines
|March 28, 2024
概括
本研究探讨使用先进的无形和纳米晶磁材料来提高电磁继电器的性能. 取代传统材料显著改善动态特性,优化继电器设计.
科学领域:
- 材料科学 材料科学 材料科学
- 电气工程 电气工程
- 电磁主义 电磁主义
背景情况:
- 软磁材料的特性极大地影响了电磁继电器的动态.
- 像电气纯铁这样的传统材料在先进的继电器优化方面存在局限性.
- 高频磁性属性是改善继电器性能的关键.
研究的目的:
- 研究无形和纳米晶体软磁材料在电磁继电器中的应用.
- 通过材料替代,增强电磁继电器的动态特性.
- 通过使用新型磁性材料验证继电器设计的模拟方法.
主要方法:
- 在继电器操作过程中对线圈电流的波形分析.
- 基于高频特性选择无形和纳米晶磁材料.
- 开发和测试一个扩大规模的原型,用于动态特性评估.
- 改进模拟方法,以准确预测中继性能.
主要成果:
- 无形和纳米晶体材料表现出优越的高频磁性.
- 改进的模拟方法可以更准确地预测中继动态特性.
- 使用新材料的六个替代方案显示了性能提升的潜力.
- 测试证实,新材料的继电器动态特性得到了显著的改善.
结论:
- 无形和纳米晶体软磁性材料为电磁继电器的传统材料提供了可行的替代方案.
- 这些先进材料的应用导致了更好的动态特性和优化的继电器设计.
- 经过验证的模拟技术促进了新型磁性材料在电磁系统中的有效集成.
相关概念视频
01:31Ferromagnetism
2.4K
Materials like iron, nickel, and cobalt consist of magnetic domains, within which the magnetic dipoles are arranged parallel to each other. The magnetic dipoles are rigidly aligned in the same direction within a domain by quantum mechanical coupling among the atoms. This coupling is so strong that even thermal agitation at room temperature cannot break it. The result is that each domain has a net dipole moment. However, some materials have weaker coupling, and are ferromagnetic at lower...
2.4K
01:25Directional Relays
110
Directional relays, essential for managing unidirectional fault currents, enhance the safety and efficiency of power systems. On power lines equipped with directional relays, faults downstream (to the right) of the current transformer typically cause the fault current to lag the bus voltage by approximately 90 degrees, known as the forward direction. In contrast, upstream (left-side) faults may result in the fault current leading the bus voltage by nearly 90 degrees, termed the reverse...
110
01:22Magnetic Force On Current-Carrying Wires: Example
1.5K
In a magnetic field, moving charges encounter a force. If a wire contains these moving charges, i.e., if the wire is carrying a current, then a force acts on the wire as well. Consider a pair of flexible leads holding a wire that is 40 cm long and 10 g in weight in a horizontal position. The wire is placed in a constant magnetic field of 0.40 T, as shown in Figure 1(a). Determine the magnitude and direction of the current flowing in the wire needed to remove the tension in the supporting leads.
1.5K
01:20Differential Relays
134
Differential relays are used to protect generators, buses, and transformers by comparing electrical quantities at different points. When a fault occurs, the difference in current between the two points triggers the relay to operate, opening the circuit breaker. Under normal conditions, the current entering (i1) and leaving (i2) a generator are equal. When a fault occurs, however, these currents become unequal, and the difference current flows in the relay operating coil, causing the relay to...
134
01:22Motional Emf
3.2K
Magnetic flux depends on three factors: the strength of the magnetic field, the area through which the field lines pass, and the field's orientation with respect to the surface area. If any of these quantities vary, a corresponding variation in magnetic flux occurs. If the area through which the magnetic field lines are passing changes, then the magnetic flux also changes. This change in the area can be of two types: the flux through the rectangular loop increases as it moves into the...
3.2K
01:13Magnetic Force Between Two Parallel Currents
3.5K
Two long, straight, and parallel current-carrying conductors exert a force of equal magnitude on one another. The direction of the force depends on the current direction in the conductors.
The force exerted by the magnetic field due to the first conductor over a finite length of the second conductor is given as the product of the current in the second conductor and the vector product of the length vector along the current element and the field due to the first conductor. According to the...
The force exerted by the magnetic field due to the first conductor over a finite length of the second conductor is given as the product of the current in the second conductor and the vector product of the length vector along the current element and the field due to the first conductor. According to the...
3.5K