Swarm 和 UNOISE 的性能优于 DADA2 和 Deblur 的性能,因为它们能够对多样性较高的海底样本进行排泄
Tonje Nilsen1, Lars-Gustav Snipen1, Inga Leena Angell1
1Faculty of Chemistry, Biotechnology and Food Science (KBM), Norwegian University of Life Sciences (NMBU), Chr. M. Falsensvei 18, Biotechnology Building, 1432 Ås, Norway.
ISME communications
|June 14, 2024
概括
对于高度多样化的海底样本,Swarm和UNOISE在元编码的序列变异分辨率方面表现优于DADA2和Deblur. 这些工具更好地捕捉了微生物社区的多样性,并准确地确定了关键的考古群体.
科学领域:
- 微生物生态学 微生物生态学
- 生物信息学是一种生物信息学.
- 分子生物学分子生物学
背景情况:
- 元编码依赖于精确的序列变异分辨率来分析微生物群落.
- 现有的工具缺乏对海洋沉积物等高度多样化的环境样本进行全面的基准测试.
研究的目的:
- 为了对四种序列变异分辨器工具 (DADA2,Deblur,Swarm,UNOISE) 的高多样性元编码数据的性能进行基准测试.
- 在复制样本,DNA提取套件和生物先验知识中比较工具性能.
主要方法:
- 评估了DADA2,Deblur,Swarm和UNOISE,使用来自30个海底沉积物样本的1800个序列变异表.
- 分析了生物复制品和五个DNA提取套件的变异.
- 评估了与已知的高多样性 (Nitrosopumilus) 和低多样性 (Sulfurovum) 考古群体的α多样性相关性.
主要成果:
- 与DADA2 (1.14) 相比,Swarm在复制样本 (曼哈顿距离0.93) 之间的差异最小.
- UNoise显示了与Nitrosopumilus alpha多样性的最强的相关性 (斯皮尔曼 rho = 0.85),而DADA2显示最弱 (0.10).
- 德布尔完全去除了Nitrosopumilus;所有方法对Sulfurovum进行了比较.
结论:
- 建议使用Swarm和UNOISE而不是DADA2和Deblur来分析高多样性海洋沉积物元编码数据.
- 工具选择对复杂环境中的序列变异分辨率和生态解释产生重大影响.
- 标准化的基准测试对于可靠的元编码研究至关重要.
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