对于斯里兰卡成年人的雷文标准渐进矩阵的年龄分层规范
Tharaka L Dassanayake1, Dewasmika I Ariyasinghe2, Anuradha Baminiwatta3
1Department of Physiology, Faculty of Medicine, University of Peradeniya, Peradeniya, Sri Lanka.
The Clinical neuropsychologist
|June 28, 2024
概括
这项研究在斯里兰卡成年人中建立了雷文标准渐进矩阵 (SPM) 的年龄分层规范. 斯里兰卡的老年人得分低于西方同行,突出了对本地认知评估工具的需求.
科学领域:
- 心理测量 心理测量 心理测量
- 认知心理学 认知心理学
- 跨文化心理学 跨文化心理学
背景情况:
- 标准化认知评估对于评估一般智力能力至关重要.
- 像雷文标准渐进矩阵 (SPM) 等测试的现有规范可能无法准确地反映多样化的群体.
- 斯里兰卡独特的社会经济和教育轨迹需要特定区域的规范性数据.
研究的目的:
- 开发针对斯里兰卡成年人量身定制的乌标准渐进矩阵 (SPM) 的年龄分层规范数据.
- 为斯里兰卡人口评估一般智力能力提供可靠的工具.
- 在斯里兰卡调查与年龄相关的认知表现模式.
主要方法:
- 610名斯里兰卡成年人 (18-72岁) 的样本完成了60项的SPM.
- 数据被分为五年年龄段,以创建百分位表和曲线.
- 使用曲线和线性回归模型来分析与年龄相关的变化.
主要成果:
- 与年龄相关的认知变化最好通过曲线模型 (R2 = 0.961) 预测.
- 斯里兰卡成年人,特别是老年人,在SPM上得分较低,与美国和英国的标准相比.
- 在较年轻的年龄组中观察到天花板效应,斯里兰卡和西方规范之间的差异在较年轻的年龄组中减少.
结论:
- 开发的SPM规范解决了斯里兰卡评估一般智力能力的关键差距.
- 观察到的绩效差异部分归因于斯里兰卡和西方样本之间的教育差异.
- 斯里兰卡的快速发展表明,这些规范需要未来的重新标准化才能保持相关性.
相关概念视频
Regression Toward the Mean
Regression toward the mean (“RTM”) is a phenomenon in which extremely high or low values—for example, and individual’s blood pressure at a particular moment—appear closer to a group’s average upon remeasuring. Although this statistical peculiarity is the result of random error and chance, it has been problematic across various medical, scientific, financial and psychological applications. In particular, RTM, if not taken into account, can interfere when researchers try to extrapolate results...
Range Rule of Thumb to Interpret Standard Deviation
The range rule of thumb in statistics helps us calculate a dataset's minimum and maximum values with known standard deviation. This rule is based on the concept that 95% of all values in a dataset lie within two standard deviations from the mean.
For instance, the range rule of thumb can be used to find the tallest and the shortest student in a class, given the mean student height and standard deviation. If the mean student height is 1.6 m and the standard deviation, s is 0.05 m, the height of...
For instance, the range rule of thumb can be used to find the tallest and the shortest student in a class, given the mean student height and standard deviation. If the mean student height is 1.6 m and the standard deviation, s is 0.05 m, the height of...


