罗达宁衍生乙醇反应产生1,3-二甲基和混合二硫化物.
Jos J A G Kamps1, Dong Zhang1, Timothy D W Claridge1
1Chemistry Research Laboratory, Department of Chemistry and the Ineos Oxford Institute for Antimicrobial Research, University of Oxford Oxford OX1 3TA UK christopher.schofield@chem.ox.ac.uk.
RSC medicinal chemistry
|July 19, 2024
概括
罗达宁化合物可以转化为乙乙醇,它们是酶抑制剂. 在DMSO中,这些乙醇二聚变为1,3-二甲基和混合二硫化物,这表明在罗丹研究中要谨慎选择溶剂.
科学领域:
- 药用化学 医学化学
- 有机化学 有机化学
- 生物化学 生物化学
背景情况:
- 罗达尼因被认为是药物开发的挑战,尽管在糖尿病治疗和正在进行的临床试验中有一些应用.
- 罗丹可以水解,形成乙乙醇,已知是金属酶的抑制剂,如金属β-乳酸酶.
研究的目的:
- 为了研究罗丹衍生物乙醇在二甲基硫氧化物 (DMSO) 中的化学转化.
- 了解罗丹和埃尼醇衍生物产生多种反应产物的潜力.
主要方法:
- 罗丹衍生物的化学表征.
- 在DMSO中形成的反应产物的分析.
主要成果:
- 观察到,罗丹衍生型乙醇在DMSO中进行二元化.
- 确定的二聚化产物是1,3-二甲基和混合二硫化物.
- 这项研究强调了罗丹和埃尼醇形成多种产品的倾向.
结论:
- 由于潜在的二元化,二甲基硫氧化物 (DMSO) 应谨慎使用作为罗丹和埃尼的储存溶剂.
- 需要进一步研究乙醇及其混合二硫化物衍生物的生物相关性.
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