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通过有机酸辅助的固体液体提取,从生物燃料灰中回收营养
Donata Drapanauskaitė1, Karolina Barčauskaitė1, Kristina Bunevičienė1
1Lithuanian Research Centre for Agriculture and Forestry, Instituto al.1, LT-58344, Akademija, Kedainiai District, Lithuania.
Chemosphere
|July 26, 2024
概括
这项研究探讨了利用有机酸从生物燃料灰中提取植物营养素 (P,K,Ca,Mg). 酸对大多数营养素显示出高效率,而酸对恢复最好.
科学领域:
- 环境科学 环境科学
- 农业化学 农业化学
- 材料科学 材料科学 材料科学
背景情况:
- 生物燃料灰是有价值的植物营养素的潜在来源.
- 这些营养素的有效回收对于可持续农业和废物利用至关重要.
- 传统的提取方法可能不高效或对环境有害.
研究的目的:
- 研究从生物燃料灰中提取 (P), (K), (Ca) 和 (Mg) 的固体液体.
- 为了比较酸,酸和酸作为浸出剂的有效性.
- 确定最佳的提取条件,以最大限度地恢复营养.
主要方法:
- 在0.1M度下使用弱有机酸 (酸,酸,酸) 进行固体-液体提取.
- 测试了多种不同的提取时间 (30,120,180分钟).
- 量化了液中的营养度,并评估了重金属污染. 扫描电子显微镜与能量分散式X射线光谱学 (SEM-EDS) 用于分析沉物形成.
主要成果:
- 0.1M酸实现了高回收率:81.9%P,82.4%Ca,76.8%Mg (在30-120分钟).
- 0.1M氧化酸产生了最高的K回收率 (59.3%在180分钟),但较低的P (80.7%),Ca (2.3%) 和Mg (68.6%) 回收.
- 液中重金属 (Zn,Al,Fe) 的污染最小;观察到氧酸与氧酸的形成.
结论:
- 没有单一的有机酸和提取时间是从生物燃料灰中回收所有目标营养素 (P,K,Ca,Mg) 的最佳时间.
- 为了有效的营养回收,需要采用涉及不同剂和时间的量身定制的提取策略.
- 生物燃料灰可以成为植物营养素的可行来源,采用适当的提取技术,最大限度地减少重金属的释放.
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