关于单点突变如何改变自身抗体谱的机制性见解
Zhong Ni1, Fangyuan Song1, Huimin Zhou1
1School of Life Sciences, Jiangsu University, Zhenjiang, 212013, China.
The protein journal
|July 28, 2024
概括
自抗体中的单个突变可以通过破坏关键的pi-pi堆叠相互作用来取消DNA结合. 这项研究揭示了重链互补性决定区域2 (H-CDR2) 是结合,影响抗体工程的关键.
科学领域:
- 分子生物学分子生物学
- 免疫学 免疫学 免疫学
- 生物化学 生物化学
背景情况:
- 自体抗体可能因单点突变而失去DNA结合能力,例如重链互补性决定区域1 (H-CDR1) 中的F33到Y.
- 这种功能丧失背后的精确分子机制仍然不完全理解.
研究的目的:
- 阐明H-CDR1中F33到Y突变导致抗DNA抗体失去DNA结合能力的分子机制.
- 研究不同抗体区域和相互作用类型对单链DNA (ssDNA) 结合的贡献.
主要方法:
- 计算分析以评估相互作用力 (静电,键,pi-pi堆叠).
- 在抗DNA抗体中的关键残留物 (F33H,W98H,Y95L) 的位点定向突变发生.
- 在CHO细胞中表达和净化野生型和突变抗体.
- 与酶相关的免疫吸收试验 (ELISA) 用于评估ssDNA结合亲和力.
主要成果:
- 静电力不是抗DNA抗体-ssDNA相互作用的主要驱动因素;H-CDR2显著促进结合,甚至比H-CDR1.
- F33Y突变增强了结,但破坏了抗体和ssDNA之间的必不可少的pi-pi堆叠相互作用.
- 野生型抗体残留物F33H,W98H和Y95L形成稳定的pi-pi与ssDNA基堆叠,这是Y33突变中丢失的关键相互作用.
结论:
- F33Y突变取消了ssDNA结合,主要是通过破坏关键的pi-pi堆叠相互作用,而不是静电力.
- H-CDR2在ssDNA结合中扮演的角色比以前被认为的更为重要.
- 了解这些相互作用对于抗体工程和开发向治疗至关重要.
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