关于统计学意义,以及缺乏这一点
Fulvio Magara1, Benjamin Boury-Jamot1
1Dept of Psychiatry, Center for Psychiatric Neurosciences, Lausanne University Hospital, Switzerland.
Laboratory animals
|August 19, 2024
概括
解释非显著的频率测试结果需要谨慎. 相当性测试,就像两种单面t测试一样,有助于确定观察到的效应是否真的不存在,或者由于样本大小小,只是在统计上无法检测到的.
科学领域:
- 生物统计学 生物统计学
- 统计推理 统计推理
- 临床试验设计 临床试验设计
背景情况:
- 缺乏统计学意义 (p>0.05) 通常被误解为没有差异或治疗效果的证据.
- 小样本大小可能会导致非显著的结果,掩盖真正的效果.
研究的目的:
- 突出解释非显著的频率测试作为无效的局限性.
- 介绍和解释等效测试的实用性,特别是两个单面的t测试,以确定没有有意义的影响.
- 为了证明等价性测试如何验证统计学显著发现的生物相关性.
主要方法:
- 解释两个单面t测试 (一种等效测试) 背后的原则.
- 作为同等性测试的先决条件,对最小的感兴趣效应大小 (SESOI) 的定义.
- 应用等效测试来解释经典t测试结果的说明性示例.
主要成果:
- 相当性测试提供了一个统计学上合理的方法来得出没有有意义的影响的结论.
- 两种单面的t测试允许在经典的t测试产生非显著结果时进行正确的解释.
- 相当性测试可以确认大样本中的重要发现是否也具有生物学意义.
结论:
- 仅仅依赖p值>0.05可能会导致关于没有影响的错误结论.
- 通过预先定义最小的相关差异,等价性测试提供了一种可靠的方法来确认没有有意义的影响.
- 整合等效测试可以提高统计结果的解释,确保统计和实际意义.
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