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在MoS₂电极中,兴奋剂诱导的进化增强

Sander Ø Hanslin^1,2, Hannes Jónsson², Jaakko Akola^1,3

¹Department of Physics, Norwegian University of Science and Technology, NO-7491, Trondheim, Norway.

Chemphyschem : a European journal of chemical physics and physical chemistry

|August 23, 2024

概括

兴奋剂MoS2与Co,Ni和Pt的边缘显著降低了进化的过度潜力. 兴奋剂保持高活性,而和减少它,提供了关于催化剂设计的见解.

科学领域:

材料科学材料科学材料科学
计算化学计算化学
电化学电化学电化学

背景情况:

进化反应 (HER) 对清洁能源技术至关重要.
二硫化物 (MoS2) 是HER的有希望的催化剂,但它的活性可以通过兴奋剂来调整.
了解杂质对MoS2的影响是优化其催化性能的关键.

研究的目的:

研究Co,Ni和Pt杂质对MoS2.2的演化反应 (HER) 的影响.
阐明反应机制并确定活性位点.
为了将理论计算与实验观察相关联起来.

主要方法:

密度函数理论 (DFT) 计算以在被杂的MoS2.2上建模HER.
速率理论用于分析反应路径和动力学.
对边缘和基底平面缺陷点的调查.

主要成果:

兴奋剂MoS2边缘与Co,Ni和Pt显著降低了HER的过剩潜力,特别是在25%的替代.
添加的MoS2在全边置换时保持高度活性,而Ni和Pt导致失活.
基底平面的内在活动源于三重S空位配置中的Mo原子的低协调,杂质相互作用导致失活.

结论:

稳定二 (H2*) 中介的稳定对于HER在化MoS2.2上的活性至关重要.
兴奋剂度和杂质类型强烈影响HER的表现,解释实验变化.
DFT和速率理论为设计基于MoS2.2的高效HER催化剂提供了宝贵的见解.

关键词:

计算电催化剂的电催化.在大法典的DFT中,大法典的DFT.的进化的进化的进化隐含的解决方法隐含的解决方法二硫化物是一种二硫化物.

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Catalysis

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