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Updated: Jun 7, 2025

Facile Preparation of 4-Substituted Quinazoline Derivatives
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Published on: February 15, 2016

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通过imine CN自由旋转引起的化物复合物的阳光诱导降解:对离子复合物的传感,结合和降解研究

Poomanirajeshwari Kathirvelu1, Murugan Gowripriya1, Ariputhiran Muthulakshmi1

  • 1International Research Centre, Centre for Supramolecular Chemistry, Kalasalingam Academy of Research and Education (KARE), Anand Nagar, Krishnankoil, Srivilliputtur, Tamil Nadu 626 126, India.

Spectrochimica acta. Part A, Molecular and biomolecular spectroscopy
|November 16, 2024
PubMed
概括

这项研究引入了一种新的基于斯奎拉的受体,可以通过颜色变化检测化物离子. 暴露在阳光下,化物复合物降解,释放离子和受体.

关键词:
CH - 离子相互作用.颜值测量传感器的颜色测量传感器化物传感器的化物传感器在M.E.P表面上方块化 方块化 方块化

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Arenediazonium substitution reactions occur when the diazonium group is substituted by various functional groups such as halides, hydroxyl, nitrile, etc. For instance, arenediazonium salts react with copper(I) salts of chloride, bromide, or cyanide to form corresponding aryl chlorides, bromides, and nitriles. These reactions are named Sandmeyer reactions. Although the mechanism of this reaction is complicated, as illustrated in Figure 1, they are believed to progress via an aryl copper...
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The reaction of weakly electrophilic aryldiazonium (also called arenediazonium) salts with highly activated aromatic compounds leads to the formation of products with an —N=N— link, called an azo linkage. This reaction, presented in Figure 1, is known as diazo coupling and occurs without the loss of the nitrogen atoms of the aryldiazonium salt. Highly activated aromatic compounds such as phenols or arylamines favor the diazo coupling reaction. The coupling generally occurs at the...
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Cyanohydrins are formed when cyanide nucleophiles and carbonyl compounds like aldehydes and ketones react. A strong base, the cyanide ion, catalyzes cyanohydrin formation. The ions are generated from HCN under aqueous conditions. Once the cyanide ions are generated, the first step involves the nucleophilic attack of the cyanide ions on the electrophilic carbonyl carbon. This attack shifts the π electrons from the C=O to the oxygen atom forming the alkoxide ion intermediate. The alkoxide anion...
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