在异形足症患者的庞塞蒂正过程中的动力学合:定量分析
Anil Agarwal1, Sitanshu Barik2, Yogesh Patel1
1Chacha Nehru Bal Chikitsalaya, New Delhi, India.
Journal of clinical orthopaedics and trauma
|December 10, 2024
概括
脚治疗中的动力学合显示了庞塞蒂技术中脚部运动之间的不一致关系. 更显著的关联出现在更晚的纠正中,特别是在脚背部屈曲和足部绑架之间.
科学领域:
- 整形外科 整形外科 整形外科
- 儿科整形外科 儿科整形外科
- 生物机械分析 生物机械分析
背景情况:
- 脚是一种复杂的先天性足部形,需要有效的治疗.
- 庞塞蒂技术是用于纠正脚的广泛使用的方法.
- 了解脚部运动的动力学合对于优化治疗结果至关重要.
研究的目的:
- 量化和关联的足部绑架的动力学合,反转,脚跟瓦鲁斯和脚equinus在俱乐部脚用Ponseti技术治疗.
- 在庞塞蒂方法的不同阶段分析这些参数之间的关系.
主要方法:
- 利用Dimeglio得分和放射角度来测量足部绑架,脚跟,脚和脚的反转.
- 在三个时间点收集数据:治疗开始 (T1),切割前 (T2) 和切割后 (T3).
- 计算了合节奏和相关系数,以评估动力学参数之间的关系.
主要成果:
- 在操纵阶段,合节奏有所变化 (例如,在1:0.3时将脚拉到马脚正).
- 切除术后,合节奏也显示出变化 (例如,1:0.5的脚背伸向脚移的变化).
- 在临床equinus和足部摘除术后之间发现了中等显著的相关性 (r=0.54,p=0.05).
结论:
- 在Ponseti治疗 clubfoot期间的动力学合是不一致的.
- 在变形纠正的后期阶段,在脚部运动之间观察到更显著的关联.
- 需要进行进一步的前性研究,才能充分理解俱乐部脚的动力学联系.
相关概念视频
Kinematic Equations - II
9.4K
The second kinematic equation expresses the final position of an object in terms of its initial position, the distance traveled with the initial constant velocity, and the distance traveled due to a change in velocity. Similar to the first kinematic equation, this equation is also only valid when the acceleration is constant throughout the motion of an object.
Suppose a car merges into freeway traffic on a 200 m long ramp. If its initial velocity is 10 m/s and it accelerates at 2 m/s2, then the...
Suppose a car merges into freeway traffic on a 200 m long ramp. If its initial velocity is 10 m/s and it accelerates at 2 m/s2, then the...
9.4K
Kinematic Equations - I
10.4K
When an object moves with constant acceleration, the velocity of the object changes at a constant rate throughout the motion. The kinematic equations of motions are derived for such cases where the acceleration of the object is constant. The first kinematic equation gives an insight into the relationship between velocity, acceleration, and time. We can see, for example:
10.4K
Kinematic Equations - III
7.5K
The first two kinematic equations have time as a variable, but the third kinematic equation is independent of time. This equation expresses final velocity as a function of the acceleration and distance over which it acts. The fourth kinematic equation does not have an acceleration term and provides the final position of the object at time t in terms of the initial and final velocities. This equation is useful when the value of the constant acceleration is unknown.
Using the kinematic equations,...
Using the kinematic equations,...
7.5K
Kinematic Equations for Rotation
315
In mechanics, when one observes a rigid body in rotational motion with constant angular acceleration, it is possible to establish equations for its rotational kinematics. This process resembles how linear kinematics are dealt with in simpler motion studies.
For instance, imagine a point A on a rigid body engaged in circular motion. The translational velocity of this particular point can be calculated by taking the time derivatives of the displacement equation, which essentially measures the...
For instance, imagine a point A on a rigid body engaged in circular motion. The translational velocity of this particular point can be calculated by taking the time derivatives of the displacement equation, which essentially measures the...
315
Development of the Limb Synovial Joints
1.3K
Joints form during embryonic development in conjunction with the formation and growth of the associated bones. The embryonic tissue that gives rise to all bones, cartilage, and connective tissues of the body is called mesenchyme.
The mesenchymal stem cells differentiate into chondrocytes that form the hyaline cartilage, and later the cartilaginous model of the bone. This model further transforms into a bone. This process is known as endochondral ossification.
During development, the limbs...
The mesenchymal stem cells differentiate into chondrocytes that form the hyaline cartilage, and later the cartilaginous model of the bone. This model further transforms into a bone. This process is known as endochondral ossification.
During development, the limbs...
1.3K
Kinematic Equations: Problem Solving
11.9K
When analyzing one-dimensional motion with constant acceleration, the problem-solving strategy involves identifying the known quantities and choosing the appropriate kinematic equations to solve for the unknowns. Either one or two kinematic equations are needed to solve for the unknowns, depending on the known and unknown quantities. Generally, the number of equations required is the same as the number of unknown quantities in the given example. Two-body pursuit problems always require two...
11.9K


