相关实验视频
Updated: Jun 5, 2025

10:09
Operation of the Collaborative Composite Manufacturing CCM System
Published on: October 1, 2019
6.6K
开发自动驾驶汽车的反向运动规划技术,使用完整的非线性约束.
1Department of Civil Engineering, Toronto Metropolitan University, 350 Victoria Street, Toronto, ON M5B2K3, Canada.
Fundamental research
|December 11, 2024
概括
本研究介绍了一种新的自动驾驶汽车运动规划技术,使用顺序轨迹和速度优化. 该方法通过使用有限元和反向方法来提高控制精度和效率,以实现更平滑,更可预测的车辆路径.
科学领域:
- 机器人和控制系统 机器人和控制系统
- 计算数学 计算数学 计算数学
背景情况:
- 自动驾驶汽车的运动规划需要复杂的轨迹和速度优化.
- 现有的方法往往面临着区分能力和约束满足方面的挑战.
研究的目的:
- 研制和验证一种用于自动驾驶汽车运动规划的新技术.
- 为了优化质量,稳定性和实时性能,比较具有不同自由度 (DOF) 的两个模型.
主要方法:
- 使用有限元素 (FE) 来表示函数,车辆动力模型和顺序二次编程来进行优化.
- 实现一个反向的方法与曲率和速度的集成多项式,和高斯的N点方程集成.
- 使用2和3DOF的断片函数,并用整体非线性取代节点线性约束.
主要成果:
- 开发的技术确保了更高的可区分性,从而产生了简单而明确的参考曲线,以提高控制精度.
- 整体非线性约束保证每个有限元素内的边界界限不会被侵犯.
- 模拟结果表明,直至最高导数,几何和动力学参数得到了光滑.
结论:
- 拟议的运动规划技术是高效的,为自动驾驶汽车提供高质量的预测.
- 该研究强调了实时应用中不同DOF模型的优化质量,稳定性和速度之间的权衡.
相关概念视频
Relative Motion Analysis using Rotating Axes-Problem Solving
389
Consider a crane whose telescopic boom rotates with an angular velocity of 0.04 rad/s and angular acceleration of 0.02 rad/s2. Along with the rotation, the boom also extends linearly with a uniform speed of 5 m/s. The extension of the boom is measured at point D, which is measured with respect to the fixed point C on the other end of the boom. For the given instant, the distance between points C and D is 60 meters.
Here, in order to determine the magnitude of velocity and acceleration for point...
Here, in order to determine the magnitude of velocity and acceleration for point...
389
PI Controller: Design
203
Proportional Integral (PI) controllers are a fundamental component in modern control systems, widely used to enhance performance and mitigate steady-state errors. They are particularly effective in applications such as automatic brightness adjustment on smartphones, where they excel at mitigating steady-state errors for step-function inputs. Unlike PD controllers, which require time-varying errors to function optimally, PI controllers leverage their integral component to address residual...
203
Velocity and Position by Integral Method
5.9K
If acceleration as a function of time is known, then velocity and position functions can be derived using integral calculus. For constant acceleration, the integral equations refer to the first and second kinematic equations for velocity and position functions, respectively.
Consider an example to calculate the velocity and position from the acceleration function. A motorboat is traveling at a constant velocity of 5.0 m/s when it starts to decelerate to arrive at the dock. Its acceleration is...
Consider an example to calculate the velocity and position from the acceleration function. A motorboat is traveling at a constant velocity of 5.0 m/s when it starts to decelerate to arrive at the dock. Its acceleration is...
5.9K
Kinematic Equations: Problem Solving
11.9K
When analyzing one-dimensional motion with constant acceleration, the problem-solving strategy involves identifying the known quantities and choosing the appropriate kinematic equations to solve for the unknowns. Either one or two kinematic equations are needed to solve for the unknowns, depending on the known and unknown quantities. Generally, the number of equations required is the same as the number of unknown quantities in the given example. Two-body pursuit problems always require two...
11.9K
Linear Approximation in Time Domain
63
Nonlinear systems often require sophisticated approaches for accurate modeling and analysis, with state-space representation being particularly effective. This method is especially useful for systems where variables and parameters vary with time or operating conditions, such as in a simple pendulum or a translational mechanical system with nonlinear springs.
For a simple pendulum with a mass evenly distributed along its length and the center of mass located at half the pendulum's length,...
For a simple pendulum with a mass evenly distributed along its length and the center of mass located at half the pendulum's length,...
63
Equation of Motion: General Plane motion - Problem Solving
170
Consider a lawn roller with a mass of 100 kg, a radius of 0.2 meters, and a radius of gyration of 0.15 meters. A force of 200 N is applied to this roller, angled at 60 degrees from the horizontal plane. What will be the angular acceleration of the lawn roller?
The friction between the roller and the ground is characterized by two coefficients. The static friction coefficient is 0.15, while the kinetic friction coefficient is 0.1. These values are crucial in understanding the interaction between...
The friction between the roller and the ground is characterized by two coefficients. The static friction coefficient is 0.15, while the kinetic friction coefficient is 0.1. These values are crucial in understanding the interaction between...
170

