使用HCO3--增强的Ru (III) /NaClO工艺高效地去除有机污染物
Yuhan Zhang1,2, Guilong Peng1,3, Yuting Yan1
1State Key Laboratory of Resource Insects, College of Sericulture, Textile and Biomass Sciences, Southwest University, Chongqing 400715, China.
International journal of molecular sciences
|January 25, 2025
概括
添加二碳酸 (NaHCO3) 显著提高了 (III) /二化物 (NaClO) 工艺的效率,以去除水中的酸7 (AO7). 这种环保的方法在中性或性条件下增强了污染物的降解.
科学领域:
- 环境催化剂环境催化剂
- 先进的氧化过程 (AOPs)
背景情况:
- 双碳酸盐在自然水中的存在给先进的氧化过程带来了挑战.
- 在二碳酸盐存在的情况下优化AOP对于有效的环境修复至关重要.
研究的目的:
- 通过使用二碳酸 (NaHCO3) 来研究 (III) /二化物 (NaClO) 系统用于酸7 (AO7) 除去的增强作用.
- 阐明二碳酸盐在催化机制中的作用及其对污染物降解效率的影响.
主要方法:
- 使用NaClO/Ru(III) 系统添加NaHCO3处理受AO7.7污染的水.
- 在pH范围6.9-10.0.0之间分析降解效率和反应动力学.
- 确定参与降解过程的关键反应物种,如Ru(V) = O.
主要成果:
- NaHCO3在6.9-10.0.0.的pH范围内的Ru (III) /NaClO系统中显著提高了AO7去除效率.
- 碳酸离子 (HCO3-) 的存在增强了Ru(III) 的激活,形成Ru(III) -HCO3-中间体.
- 增加NaHCO3度导致AO7去除速率常数增加2倍至4倍.
结论:
- 碳酸是一种有效和环保的添加剂,用于增强基于Ru (III) /NaClO的AOP.
- 该研究提出了一种新的污染物去除策略,利用无机配体来提高催化过程的性能.
- 这些发现强调了这种增强系统在现实世界水处理场景中的潜在应用.
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