估计一个数学模型的模型参数,用于手动在圆柱形抓取过程中
概括
这项研究估计了人类手指运动参数,使用了新的肌肉骨模型和运动捕捉数据. 开发的模型准确地预测了手指关节的运动,为各种掌握提供了对生物力学的见解.
科学领域:
- 生物力学 生物力学
- 人类运动分析分析
- 数学建模的数学建模
背景情况:
- 了解人类手指的生物力学对于假肢,康复和机器人技术至关重要.
- 需要精确的肌肉骨模型来模拟和预测手指的运动.
- 现有的模型可能无法完全捕捉被动时刻和肌肉缩放的复杂动态.
研究的目的:
- 开发和验证人类手指段的新型肌肉骨模型.
- 用最小平方优化方法估计被动时刻和肌肉骨缩放系数.
- 评估模型能够准确地表示个体手指动力学的能力.
主要方法:
- 使用了一种新的肌肉骨模型作为执行系统.
- 使用最小平方优化来估计模型参数.
- 将模型预测的角度数据与运动捕捉系统数据进行比较.
主要成果:
- 在模型预测和过的运动捕捉数据 (R2 = 0.98) 之间取得了高度一致性.
- 发现参数估计是个体和特定数据集的独特特征.
- 演示了模型捕捉人类手指运动动态的能力.
结论:
- 开发的数学模型和参数估计方法为人类手指生物力学提供了准确的见解.
- 该模型成功地确定了独特的被动时刻和肌肉骨缩放系数.
- 这种方法具有在各种掌握类型和个性化生物机械分析中应用的潜力.
相关概念视频
Linear Approximation in Time Domain
59
Nonlinear systems often require sophisticated approaches for accurate modeling and analysis, with state-space representation being particularly effective. This method is especially useful for systems where variables and parameters vary with time or operating conditions, such as in a simple pendulum or a translational mechanical system with nonlinear springs.
For a simple pendulum with a mass evenly distributed along its length and the center of mass located at half the pendulum's length,...
For a simple pendulum with a mass evenly distributed along its length and the center of mass located at half the pendulum's length,...
59
Two-Dimensional Force System: Problem Solving
524
Solving problems related to two-dimensional force systems is an essential aspect of mechanics and engineering. By applying the principles of vector analysis and force equilibrium, one can determine the effect of multiple forces acting on an object in a two-dimensional space.
The first step to solving a two-dimensional force system problem is to draw a free-body diagram of the object under consideration. This diagram helps identify all the external forces acting on the object, including their...
The first step to solving a two-dimensional force system problem is to draw a free-body diagram of the object under consideration. This diagram helps identify all the external forces acting on the object, including their...
524
Equation of Motion: General Plane motion - Problem Solving
166
Consider a lawn roller with a mass of 100 kg, a radius of 0.2 meters, and a radius of gyration of 0.15 meters. A force of 200 N is applied to this roller, angled at 60 degrees from the horizontal plane. What will be the angular acceleration of the lawn roller?
The friction between the roller and the ground is characterized by two coefficients. The static friction coefficient is 0.15, while the kinetic friction coefficient is 0.1. These values are crucial in understanding the interaction between...
The friction between the roller and the ground is characterized by two coefficients. The static friction coefficient is 0.15, while the kinetic friction coefficient is 0.1. These values are crucial in understanding the interaction between...
166
Angle of Twist: Problem Solving
255
An electric motor applies a torque of 700 N·m to an aluminum shaft, triggering a stable rotation. Two pulleys, B and C, are subjected to torques of 300 N·m and 400 N·m, respectively. The modulus of rigidity is provided as 25 GPa. With the knowledge of the length and diameter of each segment, the twist angle between the two pulleys can be computed. First, a section cut is made between pulleys B and C, and the cut cross-section is analyzed using a free-body diagram. Given that the...
255
Rigid Body Equilibrium Problems - I
4.3K
A rigid body is said to be in static equilibrium when the net force and the net torque acting on the system is equal to zero. To solve for rigid body equilibrium problems, do the following steps.
4.3K
Rolling Resistance: Problem Solving
279
Rolling resistance, also known as rolling friction, is the force that resists the motion of a rolling object, such as a wheel, tire, or ball, when it moves over a surface. It is caused by the deformation of the object and the surface in contact with each other, as well as other factors like internal friction, hysteresis, and energy losses within the materials. Rolling resistance opposes the object's motion, requiring additional energy to overcome it and maintain movement. In practical...
279


