乳酸代谢通过MCT1将端板和核脉之间合在一起,这对于椎间盘健康至关重要
bioRxiv : the preprint server for biology
|March 10, 2025
概括
细胞核 (NP) 细胞分泌乳酸,对于椎间盘 (ID) 的生长至关重要. 如果没有这种乳酸盐,就会发生磁盘退化,突出显示代谢合.
科学领域:
- 生物化学 生物化学
- 细胞生物学 细胞生物学
- 骨生物学 骨生物学
背景情况:
- 椎间盘 (IVD) 依赖于骨生长过程中的代谢过程.
- 核脉 (NP) 细胞具有甘油性,分泌乳酸盐.
- 乳酸在IVD发育和健康中的作用尚未完全理解.
研究的目的:
- 研究乳酸及其载体单碳酸载体1 (MCT1) 在椎间盘 (IVD) 发育和健康中的作用.
- 为了阐明核脉 (NP) 和端板 (EP) 细胞之间的代谢相互作用.
主要方法:
- 产生特定于Mct1 (Slc16a1) 淘汰赛小鼠的纤维环 (AF) 和末板 (EP).
- IVDs. 的组织学和空间转录组分析.
- 代谢测试用于评估细胞代谢和乳酸利用率.
主要成果:
- 在AF和EP中Mct1的缺乏导致了显著的IVD退化,其特征是NP细胞损失和EP成熟的延迟.
- 乳腺细胞代谢乳酸,促进蛋白质乳酸和表观遗传编程.
- 缺少NP衍生乳酸导致NP和AF细胞的葡萄糖可用性降低,导致退化.
结论:
- 在骨生长过程中,NP衍生的乳酸对于促进EP软骨转化为子冠状骨的转化至关重要.
- 乳酸介导的NP和EP细胞之间的代谢合对于IVD生长和恒温至关重要.
- 这种代谢轴的破坏有助于IVD退化.
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