相关实验视频

Updated: May 23, 2025

Dielectric RheoSANS — Simultaneous Interrogation of Impedance, Rheology and Small Angle Neutron Scattering of Complex Fluids
07:51

Dielectric RheoSANS — Simultaneous Interrogation of Impedance, Rheology and Small Angle Neutron Scattering of Complex Fluids

Published on: April 10, 2017

10.3K

Zig-Zag ScAlN 12 层切割模式 BAW 变压器应用在 Rectenna 中

Sarina Kinoshita, Rei Karasawa, Yohkoh Shimano

    IEEE transactions on ultrasonics, ferroelectrics, and frequency control
    |March 10, 2025
    PubMed
    概括

    研究人员开发了使用ScAlN薄膜的GHz批量声波压电变压器,用于物联网传感器中高效的无线电力传输. 这些微型变压器实现了显著的电压增益,超过了传统充电的性能.

    更多相关视频

    In Situ Transmission Electron Microscopy with Biasing and Fabrication of Asymmetric Crossbars Based on Mixed-Phased a-VOx09:49

    In Situ Transmission Electron Microscopy with Biasing and Fabrication of Asymmetric Crossbars Based on Mixed-Phased a-VOx

    Published on: May 13, 2020

    4.0K
    In situ Grazing Incidence Small Angle X-ray Scattering on Roll-To-Roll Coating of Organic Solar Cells with Laboratory X-ray Instrumentation06:49

    In situ Grazing Incidence Small Angle X-ray Scattering on Roll-To-Roll Coating of Organic Solar Cells with Laboratory X-ray Instrumentation

    Published on: March 2, 2021

    6.2K

    相关概念视频

    Three-Winding Transformers01:19

    Three-Winding Transformers

    Three identical single-phase transformers can be configured to form a three-phase transformer connection, which involves high-voltage and low-voltage windings. The high-voltage windings are denoted by capital letters A-B-C, while the low-voltage windings are labeled with lowercase letters a-b-c, representing their respective phases. This notation helps distinguish between the high and low voltage sides of the transformer.
    In the per-unit equivalent circuit of a grounded Y-Y three-phase...
    182
    Full wave rectifier01:22

    Full wave rectifier

    A full-wave rectifier is a device that converts alternating current (AC) to direct current (DC) and is more efficient than its half-wave counterpart. It typically includes a center-tapped transformer, two diodes, and a load resistor. The secondary winding of the transformer is divided to provide two equal voltages of opposite polarities, which is the pivotal element of full-wave rectification.
    712
    Half wave rectifier01:20

    Half wave rectifier

    A half-wave rectifier is a fundamental circuit in electronics, designed to convert alternating current (AC) voltage into a unidirectional voltage. It utilizes the simplest form of diode rectification, where the circuit comprises a single diode in series with a load resistor and an AC power source.
    703
    Equivalent Circuits for Practical Transformers01:28

    Equivalent Circuits for Practical Transformers

    The practical equivalent circuits of single-phase two-winding transformers exhibit significant deviations from their idealized versions due to the inherent properties of winding resistance and finite core permeability. These properties result in real and reactive power losses, affecting the transformer's performance. Understanding these deviations is crucial for designing more efficient transformers.
    In a practical transformer, each winding exhibits resistance and leakage reactance. The...
    376
    Energy Losses in Transformers01:21

    Energy Losses in Transformers

    In an ideal transformer, it is assumed that there are no energy losses, and, hence, all the power at the primary winding is transferred to the secondary winding. However, in reality,  the transformers always have some energy losses, and, hence, the output power obtained at the secondary winding is less than the input power at the primary winding due to energy losses.
    There are four main reasons for energy losses in transformers.
    The first cause can be  the high resistance of the...
    818
    Magnetic Field Due to Two Straight Wires01:18

    Magnetic Field Due to Two Straight Wires

    Consider two parallel straight wires carrying a current of 10 A and 20 A in the same direction and separated by a distance of 20 cm. Calculate the magnetic field at a point "P2", midway between the wires. Also, evaluate the magnetic field when the direction of the current is reversed in the second wire.
    2.3K