动物试点研究不应用于估计样本大小,如果效果大小和人口变异性是未知的
Alexander D Bird1,2,3,4, Peter Jedlicka1,4, Jochen Wilhelm5,6
1Computer-Based Modelling in the field of 3R Animal Protection, ICAR3R, Faculty of Medicine, Justus Liebig University, Giessen, Germany.
ALTEX
|April 15, 2025
概括
试点研究在动物研究中估计样本大小时效果大小未知时是无效的. 这种方法可能会增加,而不是减少使用的动物总数,挑战3Rs原则.
科学领域:
- 动物福利研究 动物福利研究
- 实验设计和统计学
背景情况:
- 3R (替代,减少,改进) 是动物研究中的关键伦理原则.
- 试点研究通常被认为有助于估计样本大小,可能减少动物使用.
研究的目的:
- 调查使用试点研究进行样本大小估计的可行性,当效果大小和差异性未知时.
- 评估试点研究对用于研究的动物总数的影响.
主要方法:
- 在未知的效果大小和方差下,推导样本大小估计器的分布.
- 分析试点研究规模和主要研究规模之间的关系.
主要成果:
- 使用试点研究可靠估计样本大小是不可行的,当效应大小未知时.
- 在这种情况下,试点研究可能需要比主要研究本身更大的样本大小.
结论:
- 进行试点研究以估计样本大小并不能尽量减少在基础或临床前研究中使用动物.
- 应考虑实验设计和样本大小计算的替代方法.
更多相关视频
相关概念视频
Sample Size Calculation
3.1K
Knowledge of the sample size is the first requirement to conduct random sampling or an experiment. The sample size is the total number of units, observations, or groups (in some cases) used to get the data to estimate a population parameter. As the name suggests, the sample size is that of the sample drawn from the population and differs from the population size.
The sample size for the given experiment or sampling effort is fundamental to any study design. Sample size decides the number of...
The sample size for the given experiment or sampling effort is fundamental to any study design. Sample size decides the number of...
3.1K
One-Way ANOVA: Equal Sample Sizes
3.1K
One-Way ANOVA can be performed on three or more samples with equal or unequal sample sizes. When one-way ANOVA is performed on two datasets with samples of equal sizes, it can be easily observed that the computed F statistic is highly sensitive to the sample mean.
Different sample means can result in different values for the variance estimate: variance between samples. This is because the variance between samples is calculated as the product of the sample size and the variance between the...
Different sample means can result in different values for the variance estimate: variance between samples. This is because the variance between samples is calculated as the product of the sample size and the variance between the...
3.1K
One-Way ANOVA: Unequal Sample Sizes
5.6K
One-way ANOVA can be performed on three or more samples of unequal sizes. However, calculations get complicated when sample sizes are not always the same. So, while performing ANOVA with unequal samples size, the following equation is used:
5.6K
Estimating Population Standard Deviation
3.0K
When the population standard deviation is unknown and the sample size is large, the sample standard deviation s is commonly used as a point estimate of σ. However, it can sometimes under or overestimate the population standard deviation. To overcome this drawback, confidence intervals are determined to estimate population parameters and eliminate any calculation bias accurately. However, this only applies to random samples from normally distributed populations. Knowing the sample mean and...
3.0K
Sample Proportion and Population Proportion
5.1K
Collecting samples or responses from an entire population takes significant time and effort, so a researcher collects responses from only a sample of that population. Suppose a study needs to collect information about a specific mobile application. After sample collection, the researcher analyzes the data and discovers that most individuals in the sample use that specific mobile application. The sample proportion measures the number of individuals in a sample who either use or don't use the...
5.1K
Estimating Population Mean with Known Standard Deviation
8.2K
To construct a confidence interval for a single unknown population mean μ, where the population standard deviation is known, we need sample mean as an estimate for μ and we need the margin of error. Here, the margin of error (EBM) is called the error bound for a population mean (abbreviated EBM). The sample mean is the point estimate of the unknown population mean μ.
The confidence interval estimate will have the form as follows:
(point estimate - error bound, point estimate +...
The confidence interval estimate will have the form as follows:
(point estimate - error bound, point estimate +...
8.2K


