和硫尿素的同时应用,以减轻小麦幼苗的盐分压力
Khizir Abbas1, Muhammad Javed1, Sidra Aslam2
1Department of Botany, Division of Science and Technology, University of Education, Lahore, Pakistan.
Scientific reports
|April 26, 2025
概括
这项研究发现,198mM NaCl可将小麦生长率降低50%. 补充15mM和硫尿素通过增强离子平衡和抗氧化活性显著改善了盐分耐受性.
科学领域:
- 植物科学 植物科学
- 农业科学 农业科学
- 生物化学 生物化学
背景情况:
- 盐应激严重影响作物产量,破坏离子平衡并造成氧化损伤.
- 小麦 (Triticum aestivum) 特别容易受到盐引起的毒性,需要有效的缓解策略.
- 仅使用或抗氧化物化合物的现有缓解方法通常是不够的.
研究的目的:
- 为了确定导致小麦生长减少50%的化 (NaCl) 致命剂量.
- 评估联合 (K) 和硫尿素 (TU) 补充剂在缓解 NaCl 诱导毒性的有效性.
- 研究K和TU的保护作用背后的生理和生化机制.
主要方法:
- 一个实验室实验使用一个有三个生物复制的因数排列进行.
- 小麦受到198mM NaCl的接触,被确定为减少50%生长的度.
- 和硫尿素的组合在0mM,10mM和15mM时被应用,以评估它们的缓解作用.
主要成果:
- 198 mM NaCl 减少了50%的发芽和生长.
- 联合应用15mM和15mM硫尿素 (K15 + TU15) 显著改善了离子平衡,将离子平衡增加14%,Na+减少28.55%,K+增加23.92%.
- K15 + TU15增强了生长参数 (芽/根长度,新鲜/干燥重量),生理功能 (光合作用,口腔导电,透气,内部CO2,相对含水量),降低了氧化应激标志物 (H2O2,MDA),并增强了抗氧化酶活性 (SOD,CAT,POD,APX).
结论:
- 最佳的NaCl度减少小麦生长50%被确定为198mM.
- 同时应用15毫米和15毫米尿素有效地减轻了小麦中盐引起的毒性.
- 这种缓解是通过增强的离子平衡,减少氧化应激和增加抗氧化酶活性来实现的,从而改善了植物生长和生理功能.
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