相关实验视频
Updated: May 15, 2025

07:18
Generating Lap Joints Via Friction Stir Spot Welding on DP780 Steel
Published on: August 13, 2019
6.9K
通过表面几何学增强的合金接头的剪切阻力研究
Xiangke Zheng1,2, Ning Hu2, Linsen Shu3
1School of Optoelectronic Engineering, Xidian University, Xi'an 710126, China.
Materials (Basel, Switzerland)
|May 14, 2025
概括
激光雕刻的表面微型图案通过提高粘附性来增强2A12合金的剪切强度. 在精确的激光处理距离下,通过特定的并行和交叉波模式获得最佳结果.
科学领域:
- 材料科学 材料科学 材料科学
- 表面工程是什么?表面工程是什么?
- 粘附科学 粘附科学 粘附科学
背景情况:
- 2A12合金的粘合粘合对于结构应用至关重要.
- 提高这些接头的剪切强度是一个关键的工程挑战.
- 表面修改技术可以提高粘合剂粘合性能.
研究的目的:
- 为了研究激光雕刻的表面微型图案对2A12合金的剪切强度的影响.
- 为了比较并行和交叉波微模式的性能.
- 为了确定最佳的激光处理参数,以增强粘附性.
主要方法:
- 在2A12合金上使用激光雕刻制造平行和交叉波面微型图案.
- 对每个微型模式类型的激光处理距离的系统变化.
- 测量粘合剂结合的接头的剪切强度.
主要成果:
- 微型图案表面表现出极好的水友性,促进了与粘合剂的机械互锁.
- 平行波形微型图案显示,在0.5毫米激光处理距离下,最大切削强度为14.04 MPa.
- 交叉波微模式在0.75毫米激光处理距离下实现了13.74 MPa的峰值切削强度.
- 对平行模式来说,切削强度通常随着激光距离的增加而下降,而交叉波模式显示了最初的增加,然后下降.
结论:
- 激光雕刻的表面微型图案显著提高了2A12合金粘合剂结合的剪切强度.
- 微模式的几何形状 (平行与交叉波) 和激光处理距离是影响键强度的关键因素.
- 这些发现为设计和优化合金的接接头提供了有价值的数据.
相关概念视频
Method of Joints: Problem Solving II
475
Consider a truss structure with frictionless joints fixed to a wall and roller support. If a force of 150 N is applied to joint A, the forces in each member of the truss can be determined using the method of joints.
475
Shearing Stress
473
Shearing stress, denoted by the Greek letter tau (τ), is stress caused by forces acting transversely on an object. These forces create internal ones within the entity in the plane where the external forces are applied. The resultant of these internal forces is the shear in the section.
The average shearing stress can be calculated by dividing the shear by the area of the cross-section.
The average shearing stress can be calculated by dividing the shear by the area of the cross-section.
473
Shear on the Horizontal Face of a Beam Element
131
To understand shear on the flat side of a prismatic beam element, consider the vertical and horizontal shearing forces, and the normal forces, acting on the element. The element's upper (U) and lower (L) sections, which are divided by the beam's neutral axis, are examined. The equilibrium of these forces is determined by applying the equilibrium equation, which helps identify the horizontal shearing force. This force is directly related to the bending moments and the cross-section's...
131
Method of Joints: Problem Solving I
998
The method of joints is a commonly used technique to analyze the forces in structural trusses. The method is based on the principle of equilibrium, which assumes that the truss members are connected by frictionless pins. The forces at each joint can be determined by considering the equilibrium of the forces acting on that joint. Consider a truss structure with two forces of 20 N and 10 N acting at joints C and D, respectively. The method of joints can be used to determine the forces FCB, FDC,...
998
Relation between Poisson's ratio, Modulus of Elasticity and Modulus of Rigidity
228
Deformation occurs in axial and transverse directions when an axial load is applied to a slender bar. This deformation impacts the cubic element within the bar, transforming it into either a rectangular parallelepiped or a rhombus, contingent on its orientation. This transformation process induces shearing strain. Axial loading elicits both shearing and normal strains. Applying an axial load instigates equal normal and shearing stresses on elements oriented at a 45° angle to the load axis.
228
Shear Diagram
694
In the study of beam mechanics, shear diagrams play a crucial role in understanding the distribution of shear forces along the length of a beam. Consider a beam AB that is supported at both ends and subjected to perpendicular loads.
First, a free-body diagram of the beam is drawn, representing all the external forces and internal reactions acting on the beam. One can calculate the reaction forces at each support by employing the equilibrium equations of force and moment. The vertical component...
First, a free-body diagram of the beam is drawn, representing all the external forces and internal reactions acting on the beam. One can calculate the reaction forces at each support by employing the equilibrium equations of force and moment. The vertical component...
694

