旋转-轨道角动量转换在合的非偏向贝塞尔声学中
Di-Chao Chen1,2, Qian Mo1, Da-Jian Wu1
1Institute of Acoustics, School of Physics and Technology, Nanjing Normal University, Nanjing, 210023, China.
Advanced science (Weinheim, Baden-Wurttemberg, Germany)
|June 10, 2025
概括
研究人员展示了声学旋转轨道角动量 (AM) 转换,使微观物体能够精确无接触操纵. 这一突破为声学传感,成像和粒子控制提供了新的可能性.
科学领域:
- 声学 声学 在声学方面
- 波浪物理 波浪物理
- 纳米技术 纳米技术
背景情况:
- 纵向声波具有旋转和轨道角动量 (AM).
- 分离和测量这些AM元件是具有挑战性的.
- 直接波场测量很难研究两种AM类型.
研究的目的:
- 从理论上解释和实验证明声学旋转轨道AM转换.
- 在合的贝塞尔声中开发一个旋转轨道AM转换的公式描述.
- 通过这种现象来证明微观物体的无接触操纵.
主要方法:
- 旋转轨道AM转换在非对轴的贝塞尔声波旋中的理论导出.
- 使用被动人工结构进行实验波场测量.
- 雷利粒子旋转和循环转换的观察.
主要成果:
- 成功的理论解释和实验验证声学旋转轨道AM转换.
- 使用被动人工结构演示转换.
- 无接触,高分辨率操纵微观物体,包括控制的旋转和转移.
结论:
- 这项工作为经典波的AM物理提供了基本的见解.
- 演示的旋转轨道AM转换对声学传感和成像具有重大影响.
- 应用包括使用声波辐射力量和扭矩进行先进的粒子操纵.
相关概念视频
Conservation of Angular Momentum: Application
11.4K
A system's total angular momentum remains constant if the net external torque acting on the system is zero. Examples of such systems include a freely spinning bicycle tire that slows over time due to torque arising from friction, or the slowing of Earth's rotation over millions of years due to frictional forces exerted on tidal deformations. However in the absence of a net external torque, the angular momentum remains conserved. The conservation of angular momentum principle requires a...
11.4K
Conservation of Angular Momentum
10.8K
A system's total angular momentum remains constant if the net external torque acting on the system is zero. Considering a system that consists of n tiny particles, the angular momentum of any tiny particle may change, but the system's total angular momentum would remain constant. The principle of conservation of angular momentum only considers the net external torque acting on the system. While there are internal forces exerted by different particles within the system that also produce...
10.8K
Angular Momentum: Single Particle
6.6K
Angular momentum is directed perpendicular to the plane of the rotation, and its magnitude depends on the choice of the origin. The perpendicular vector joining the linear momentum vector of an object to the origin is called the “lever arm.” If the lever arm and linear momentum are collinear, then the magnitude of the angular momentum is zero. Therefore, in this case, the object rotates about the origin such that it lies on the rim of the circumference defined by the lever arm...
6.6K
Angular Momentum about an Arbitrary Axis
258
Imagine a rigid body with a mass denoted as 'm', which has its center of mass at point G and is rotating around an inertial reference frame. The angular momentum at an arbitrary point P can be calculated by taking the cross product of the position vector and linear momentum vector for each individual mass element.
The velocity of a mass element comprises its translational velocity and the relative velocity instigated by the body's rotation. Substituting the velocity equation into...
The velocity of a mass element comprises its translational velocity and the relative velocity instigated by the body's rotation. Substituting the velocity equation into...
258
Angular Momentum
353
Angular momentum characterizes an object's rotational motion and is defined as the moment of its linear momentum about a specified point O. When a particle moves along a curved path in the x-y plane, the scalar formulation calculates the magnitude of its angular momentum, utilizing the moment arm (d), representing the perpendicular distance from point O to the line of action of the linear momentum. Despite being scalar in formulation, angular momentum is inherently a vector quantity. Its...
353
Spin–Spin Coupling Constant: Overview
1.0K
In bromoethane, the three methyl protons are coupled to the two methylene protons that are three bonds away. In accordance with the n+1 rule, the signal from the methyl protons is split into three peaks with 1:2:1 relative intensities. The methylene protons appear as a quartet, with the relative intensities of 1:3:3:1.
Qualitatively, any spin plus-half nucleus polarizes the spins of its electrons to the minus-half state. Consequently, the paired electron in the hydrogen–carbon bond must...
Qualitatively, any spin plus-half nucleus polarizes the spins of its electrons to the minus-half state. Consequently, the paired electron in the hydrogen–carbon bond must...
1.0K


