动态贝叶斯优化用于外骨架辅助的推进力学训练的试点测试
概括
动态贝叶斯优化 (DBO) 显示了训练神经运动学习的潜力,但人在循环 (HIL) 优化需要进一步开发以进行有效的步态训练. 这项研究探讨了DBO在走路时增强尾行四肢角度 (TLA).
科学领域:
- 生物力学 生物力学
- 机器人技术 机器人技术 机器人技术
- 神经科学是一个神经科学.
背景情况:
- 人在循环 (HIL) 优化对于辅助任务是有效的,但尚未用于培训.
- 传统的HIL方法在训练期间难以将神经运动学习纳入训练.
- 神经运动学习对于适应运动模式至关重要,例如步态机制.
研究的目的:
- 实施和评估动态贝叶斯优化 (DBO) 用于步态推进力学HIL培训.
- 为了研究DBO在走路时增加后肢角 (TLA) 的作用.
- 在HIL培训环境中,将DBO与传统贝叶斯优化 (BO) 进行比较.
主要方法:
- 使用DBO进行了一个单参数HIL优化实验.
- 五名参与者在带仪器的跑步机上行走,接受外骨施加的部扭矩脉冲.
- 目标是增加后肢角 (TLA);结果与BO对照条件进行了比较.
主要成果:
- 在DBO组中,在训练后观察到TLA显著增加,但在BO组中没有.
- 在培训阶段,没有发现TLA在组级显著增加.
- 应用扭矩对TLA变化的微弱但显著的影响表明调制可实现性有限.
结论:
- 在TLA中,DBO显示了促进训练后神经运动适应的潜力.
- 当前的HIL优化范式可能不足以直接训练特定指标的步态,如TLA.
- 未来的研究应该探索多参数优化和替代推进指标,以加强步行训练.
相关概念视频
Kinematic Equations: Problem Solving
14.9K
When analyzing one-dimensional motion with constant acceleration, the problem-solving strategy involves identifying the known quantities and choosing the appropriate kinematic equations to solve for the unknowns. Either one or two kinematic equations are needed to solve for the unknowns, depending on the known and unknown quantities. Generally, the number of equations required is the same as the number of unknown quantities in the given example. Two-body pursuit problems always require two...
14.9K
Three-Dimensional Force System:Problem Solving
866
A three-dimensional force system refers to a scenario in which three forces act simultaneously in three different directions. This type of problem is commonly encountered in physics and engineering, where it is necessary to calculate the resultant force on the system, which can then be used to predict or analyze the behavior of the object or structure under consideration.
To solve a three-dimensional force system, first resolve each force into its respective scalar components. Do this using...
To solve a three-dimensional force system, first resolve each force into its respective scalar components. Do this using...
866
Work and Energy for Variable Forces
3.9K
When an object is acted upon by a variable force, the amount of work done and the change in energy of the object can be more complex to calculate compared to when a constant force is applied. Work is the product of force and displacement, while energy is the capacity of a system to do work. When a constant force is applied to an object, the work done can be calculated as the product of the force and the distance moved in the direction of the force. However, when a variable force is applied, the...
3.9K
Two-Dimensional Force System: Problem Solving
679
Solving problems related to two-dimensional force systems is an essential aspect of mechanics and engineering. By applying the principles of vector analysis and force equilibrium, one can determine the effect of multiple forces acting on an object in a two-dimensional space.
The first step to solving a two-dimensional force system problem is to draw a free-body diagram of the object under consideration. This diagram helps identify all the external forces acting on the object, including their...
The first step to solving a two-dimensional force system problem is to draw a free-body diagram of the object under consideration. This diagram helps identify all the external forces acting on the object, including their...
679
Rigid Body Equilibrium Problems - I
4.8K
A rigid body is said to be in static equilibrium when the net force and the net torque acting on the system is equal to zero. To solve for rigid body equilibrium problems, do the following steps.
4.8K
Rigid Body Equilibrium Problems - II
7.5K
A rigid body is in static equilibrium when the net force and the net torque acting on the system are equal to zero.
Consider two children sitting on a seesaw, which has negligible mass. The first child has a mass (m1) of 26 kg and sits at point A, which is 1.6 meters (r1) from the pivot point B; the second child has a mass (m2) of 32 kg and sits at point C. How far from the pivot point B should the second child sit (r2) to balance the seesaw?
Consider two children sitting on a seesaw, which has negligible mass. The first child has a mass (m1) of 26 kg and sits at point A, which is 1.6 meters (r1) from the pivot point B; the second child has a mass (m2) of 32 kg and sits at point C. How far from the pivot point B should the second child sit (r2) to balance the seesaw?
7.5K


