化物固体电解质的有益氧化还原活性,为全固态电池中的高性能阳极提供动力
Zhu Cheng1, Wenxuan Zhao1, Qidi Wang1
1Section Storage of Electrochemical Energy, Radiation Science and Technology, Faculty of Applied Sciences, Delft University of Technology, Delft, The Netherlands.
高离子导电性化物固体电解质表现出动态稳定性,使其与全固态电池中的高容量阳极兼容. 这一突破提高了电池的性能,安全性和寿命.
科学领域:
- 材料科学 材料科学 材料科学
- 电化学 电化学 电化学
- 储能 储能 储能 储能 储能 储能
背景情况:
- 全固态电池提供了更高的安全性和能量密度,但在低电位下面面临着固体电解质稳定性的挑战.
- 离子导体固体电解质在低运行潜力的分解导致损失和细胞阻力增加,限制了与高容量阳极的兼容性.
- 下一代电池需要固体电解质,可以承受低电位而不会损害离子导电性.
研究的目的:
- 为了证明固体电解质的动态稳定性,以提高全固态电池的性能.
- 为了研究化物电解质Li3YCl3Br3和Li2ZrCl6在其电化学稳定性窗口之外的电化学行为.
- 评估这些电解质与高容量阳极,特别是红色的兼容性.
主要方法:
- 化物电解质Li3YCl3Br3和Li2ZrCl6.6的电化学表征
- 研究超出电化学稳定性极限的结构可逆氧化还原活性.
- 使用化物电解质和红阳极的全固态电池的制造和测试.
主要成果:
- 化物电解质Li3YCl3Br3和Li2ZrCl6在它们典型的电化学稳定性窗口以下表现出动态稳定性和可逆的氧化还原活性.
- 证明与红色阳极的兼容性,实现高可逆容量 (2,308 mAh g-1) 和出色的速率能力 (1,024 mAh g-1 在7.75 mA cm-2).
- 在基于化物的完整电池中,实现了半电池的延长周期寿命 (在1780个循环后保持61%) 和高面积容量 (7.65 mAh cm-2),具有良好的稳定性 (在1000个循环后保持70%).
结论:
- 化物电解质的动态稳定性显著扩大了它们在先进电池设计中的适用性.
- 化物电解质中的结构可逆氧化还原活性提高了与高容量阳极的兼容性,提高了电池的性能.
- 这些发现为开发高性能,安全和持久的全固态电池提供了有价值的设计原则.
更多相关视频
07:55Elemental-sensitive Detection of the Chemistry in Batteries through Soft X-ray Absorption Spectroscopy and Resonant Inelastic X-ray Scattering
Published on: April 17, 2018
10:03Characterization of Electrode Materials for Lithium Ion and Sodium Ion Batteries Using Synchrotron Radiation Techniques
Published on: November 11, 2013
相关概念视频
Electrolysis
Voltaic/Galvanic Cells
Spontaneous redox reactions occur abundantly in nature. The chemical reaction occurring in a disposable AA battery powering our remote controls is one such example of a spontaneous redox reaction. Another example is the immersion of coiled copper wire into an aqueous silver nitrate solution. The reaction shows a gradual, visually impressive color change from colorless to bright blue and the formation of a grey precipitate on the copper wire. In this experiment,...
Standard Electrode Potentials
Batteries and Fuel Cells
Balancing Redox Equations
Acid Halides to Alcohols: LiAlH4 Reduction
The mechanism proceeds in three steps. First, the nucleophilic hydride ion attacks the carbonyl carbon of the acid halide to form a tetrahedral intermediate. Next, the carbonyl group is re-formed, and the halide ion departs as a leaving group, generating an aldehyde. A second nucleophilic attack by the hydride yields an alkoxide ion, which, upon protonation, gives a primary alcohol as...
