基于特征优化和权重空间聚类的玉米风险评估:中国山东省的一个案例研究
Yanan Zuo1, Min Ji2, Jiutao Yang3
1College of Geodesy and Geomatics, Shandong University of Science and Technology, Qingdao, 266590, China.
Scientific reports
|July 31, 2025
概括
气候变暖增加了玉米虫的爆发. 这项研究开发了一种新的机器学习模型,用于精确的风险评估和山东省的空间划分,以帮助控制害虫的努力.
科学领域:
- 农业科学 农业科学
- 数据科学数据科学数据科学
- 环境科学 环境科学
背景情况:
- 玉米挖掘机在农业中造成了重大的全球经济损失.
- 气候变暖加剧了害虫疫情,需要先进的风险评估.
- 现有的模型在空间时间风险评估中往往缺乏准确性.
研究的目的:
- 开发和验证一种新的机器学习方法来评估玉米发生风险.
- 量化山东省玉米风险的时间和空间分布.
- 为害虫管理策略提供决策支持.
主要方法:
- 为不平衡的害虫数据集构建了一个特征优化模型 (边界-SMOTE与遗传算法-随机森林).
- 为空间风险评估开发了一个加权集群算法,克服了传统方法的局限性.
- 综合自然灾害风险理论 (危险性,敏感性,能力) 用于全面的风险区分.
主要成果:
- 与原来的随机森林模型相比,改进的模型显著提高了性能指标 (OOB_score,精度,F1_score).
- 权重的K-means集群表现出优于权重的聚合层次集群和权重的DBSCAN的性能.
- 空间风险区划确定了山东西南部和北部的高风险地区,与实际情况保持一致.
结论:
- 拟议的机器学习框架为农业害虫风险评估提供了一种新有效的方法.
- 这些发现为山东省针对性地预防和控制玉米虫提供了关键数据.
- 这项研究有助于了解气候变化对害虫动态的影响,并制定适应性管理策略.
更多相关视频
相关概念视频
Cluster Sampling Method
12.8K
Appropriate sampling methods ensure that samples are drawn without bias and accurately represent the population. Because measuring the entire population in a study is not practical, researchers use samples to represent the population of interest.
To choose a cluster sample, divide the population into clusters (groups) and then randomly select some of the clusters. All the members from these clusters are in the cluster sample. For example, if you randomly sample four departments from your...
To choose a cluster sample, divide the population into clusters (groups) and then randomly select some of the clusters. All the members from these clusters are in the cluster sample. For example, if you randomly sample four departments from your...
12.8K
Quantifying and Rejecting Outliers: The Grubbs Test
2.1K
Sometimes, a data set can have a recorded numerical observation that greatly deviates from the rest of the data. Assuming that the data is normally distributed, a statistical method called the Grubbs test can be used to determine whether the observation is truly an outlier. To perform a two-tailed Grubbs test, first, calculate the absolute difference between the outlier and the mean. Then, calculate the ratio between this difference and the standard deviation of the sample. This...
2.1K


