一种基于里曼几何学的水下声学干扰抑制方法
Xueli Sheng1,2,3, Hang Dong1,2,3, Bingyu Shi1,2,3
1National Key Laboratory of Underwater Acoustic Technology, Harbin Engineering University, Harbin 150001, China.
The Journal of the Acoustical Society of America
|August 7, 2025
概括
这项研究引入了一种用于被动声纳系统的新型宽带干扰抑制方法. 该技术通过利用里曼的几何学来提高信号与干扰的比率,有效地拒绝没有事先信息的干扰.
科学领域:
- 信号处理 信号处理
- 水下声学 水下声学
- 阵列信号处理 阵列信号处理
背景情况:
- 阵列信号处理对于声纳系统至关重要,但受到强大的干扰而退化.
- 到达方向估计和目标定位对干扰特别敏感.
- 现有的方法通常需要事先提供信息,或者对宽带干扰的有效性较低.
研究的目的:
- 为被动声纳系统提出宽带干扰抑制方法.
- 为了利用里曼的几何学来改善干扰拒绝.
- 为了提高信号与干扰比率 (SIR) 没有事先的知识.
主要方法:
- 开发了一种基于赫米特正确数矩阵的里曼几何学的方法.
- 将样本共变矩阵的里曼平均值纳入常规光束成型中.
- 使用被动声纳系统数据进行验证.
主要成果:
- 拟议的方法通过创建空间光谱来有效地拒绝干扰方向.
- 与传统方法相比,实现了更好的信号与干扰比率.
- 与竞争中的干扰抑制技术相比,其表现优越.
结论:
- 基于里曼几何学的方法为被动声纳中宽带干扰抑制提供了强大的解决方案.
- 该方法有效地提高了在具有挑战性的声学环境中阵列信号处理性能.
- 通过数值模拟和实验数据比较验证的有效性.
相关概念视频
Sound Waves: Interference
3.9K
Sound waves can be modeled either as longitudinal waves, wherein the molecules of the medium oscillate around an equilibrium position, or as pressure waves. When two identical waves from the same source superimpose on each other, the combination of two crests or two troughs results in amplitude reinforcement known as constructive interference. If two identical waves, that are initially in phase, become out of phase because of different path lengths, the combination of crests with troughs...
3.9K
Interference and Superposition of Waves
5.5K
When two waves of the same nature occur in the same region simultaneously, they result in interference. Interference of waves implies that the net effect of the waves is the sum of the individual waves' effects. However, it does not imply that the individual waves affect the propagation of other waves.
Interference occurs in mechanical waves, such as sound waves, waves on a string, and surface water waves. Mechanical waves correspond to the physical displacement of particles. Hence,...
Interference occurs in mechanical waves, such as sound waves, waves on a string, and surface water waves. Mechanical waves correspond to the physical displacement of particles. Hence,...
5.5K
Interference: Path Lengths
1.4K
Consider two sources of sound, that may or may not be in phase, emitting waves at a single frequency, and consider the frequencies to be the same.
Two special sources may be considered when they are in phase. This can be easily achieved by feeding the two sources from the same source. An example would be synchronizing the two speakers by feeding them with the same source, such as the sound waves produced by a tuning fork. This setup ensures that the two sources have the same frequency and are...
Two special sources may be considered when they are in phase. This can be easily achieved by feeding the two sources from the same source. An example would be synchronizing the two speakers by feeding them with the same source, such as the sound waves produced by a tuning fork. This setup ensures that the two sources have the same frequency and are...
1.4K
Echo
602
The human ear cannot distinguish between two sources of sound if they happen to reach within a specific time interval, typically 0.1 seconds apart. More than this, and they are perceived as separate sources.
Imagine the sound is reflected back to the ears. Assuming that the source is very close to the human, the difference between hearing the two sounds—the emitted sound and the reflected sound—may be more than the minimum time for perceiving distinct sounds. If this is the case,...
Imagine the sound is reflected back to the ears. Assuming that the source is very close to the human, the difference between hearing the two sounds—the emitted sound and the reflected sound—may be more than the minimum time for perceiving distinct sounds. If this is the case,...
602
Uniform Depth Channel Flow: Problem Solving
126
To calculate the flow rate for a trapezoidal channel, first, identify the bottom width, side slope, and flow depth of the channel. The cross-sectional area (A) corresponding to the depth of flow (y), channel bottom width (B), and side slope (θ) is determined by:Next, calculate the wetted perimeter, which includes the bottom width and the sloped side lengths in contact with the water. Using the values of the cross-sectional area and the wetted perimeter, determine the hydraulic radius by...
126
Propagation of Waves
2.4K
When a wave propagates from one medium to another, part of it may get reflected in the first medium, and part of it may get transmitted to the second medium. In such a case, the interface of the two mediums can be considered as a boundary that is neither fixed nor free.
Consider a scenario where a wave propagates from a string of low linear mass density to a string of high linear mass density. In such a case, the reflected wave is out of phase with respect to the incident wave, however the...
Consider a scenario where a wave propagates from a string of low linear mass density to a string of high linear mass density. In such a case, the reflected wave is out of phase with respect to the incident wave, however the...
2.4K


