从阴离子到阳离子的Al12B和Al13集群. 中间超原子物种的芳香特征
Peter L Rodríguez-Kessler1, Alvaro Muñoz-Castro2
1Centro de Investigaciones en Óptica A.C., Loma del Bosque 115, Col. Lomas del Campestre, León, Guanajuato 37150, Mexico.
The Journal of chemical physics
|December 9, 2025
概括
具有不同电荷的 (Al13) 集群在与有机基板相互作用时表现出改变的芳香度和磁性. 这些经过修改的超原子集群仍然是先进分子材料的稳定基石.
科学领域:
- * 超原子星团科学研究
- * * 材料化学 材料化学
- * 计算化学 计算化学
背景情况:
- *集群,特别是Al13,是成熟的超原子系统.
- * Al13-集群表现出封闭外电子结构和球形芳香度.
- * 了解中间电荷状态对于集群行为至关重要.
研究的目的:
- * 调查中介Al13集群 (Al13+和中性Al13) 的电子和磁性特性.
- * 评估有机基质对集群芳香度和磁性异性质的影响.
- * 探索这些改造集群作为分子材料的构建块的潜力.
主要方法:
- *对Al13+,中性Al13及其添加的对应物进行了计算研究.
- *分析包括电子结构,集群电子数和磁性特性.
- * n型和p型有机基质的影响在理论上进行了建模.
主要成果:
- *与Al13-.相比,Al13+ (38个集群电子) 和中性Al13 (39个集群电子) 的球形芳香度较低.
- * 用添加的异电子集群表现出类似的趋势.
- * 阴离子和中性星团在不同的磁场方向下显示出对比的磁性行为,表明磁性异性变化.
结论:
- *中间的Al13集群保持稳定,尽管芳香度降低.
- * 这些集群作为基于分子的材料的稳定构建块.
- *这项研究提供了关于在基质相互作用时超原子集群行为的见解.
相关概念视频
π Molecular Orbitals of the Allyl Cation and Anion
5.3K
An allyl group is a three-carbon conjugated system where the sp³-hybridized allylic carbon is bonded to a CH=CH2 group via a single bond. Allyl anions can be obtained by treating propene with a strong base that can deprotonate methyl groups. Allyl cations are formed as intermediates during substitution reactions involving allylic halides. In both cases, the hybridization of the allylic carbon changes from sp3 to sp2, giving rise to a carbon chain with three sp2-hybridized carbons, each with...
5.3K
Electrophilic Addition to Alkynes: Halogenation
9.9K
Introduction
Halogenation is another class of electrophilic addition reactions where a halogen molecule gets added across a π bond. In alkynes, the presence of two π bonds allows for the addition of two equivalents of halogens (bromine or chlorine). The addition of the first halogen molecule forms a trans-dihaloalkene as the major product and the cis isomer as the minor product. Subsequent addition of the second equivalent yields the tetrahalide.
Halogenation is another class of electrophilic addition reactions where a halogen molecule gets added across a π bond. In alkynes, the presence of two π bonds allows for the addition of two equivalents of halogens (bromine or chlorine). The addition of the first halogen molecule forms a trans-dihaloalkene as the major product and the cis isomer as the minor product. Subsequent addition of the second equivalent yields the tetrahalide.
9.9K
Aromatic Hydrocarbon Cations: Structural Overview
3.6K
Cycloheptatriene is a neutral monocyclic unsaturated hydrocarbon that consists of an odd number of carbon atoms and an intervening sp3 carbon in the ring. The three double bonds in the ring correspond to 6 π electrons, which is a Huckel number, and therefore satisfies the criteria of 4n + 2 π electrons. However, the intervening sp3 carbon disrupts the continuous overlap of p orbitals. As a result, cycloheptatriene is not aromatic.
Removing one hydrogen from the intervening CH2 group...
Removing one hydrogen from the intervening CH2 group...
3.6K
Ionic Bonding and Electron Transfer
48.5K
Ions are atoms or molecules bearing an electrical charge. A cation (a positive ion) forms when a neutral atom loses one or more electrons from its valence shell, and an anion (a negative ion) forms when a neutral atom gains one or more electrons in its valence shell. Compounds composed of ions are called ionic compounds (or salts), and their constituent ions are held together by ionic bonds: electrostatic forces of attraction between oppositely charged cations and anions.
48.5K
Aromatic Hydrocarbon Anions: Structural Overview
3.5K
Neutral hydrocarbons like cyclopentadiene with an odd number of carbon atoms and one intervening CH2 group in the ring are not aromatic. Cyclopentadiene with 4 π electrons does not satisfy the 4n + 2 π electron rule. Additionally, the intervening CH2 group is sp3 hybridized and lacks a vacant p orbital, thereby interrupting the overlap of p orbitals in a continuous manner and preventing the delocalization of π electrons throughout the ring.
Due to the absence of continuous...
Due to the absence of continuous...
3.5K
Mass Spectrometry: Alkyl Halide Fragmentation
1.5K
Chlorine isotopes exist as 35Cl and 37Cl in a 3:1 ratio, while bromine isotopes exist as 79Br and 81Br in a 1:1 ratio. The mass spectrum of alkyl halides typically produces two distinct molecular ion peaks, the molecular ion peak, [M], and the molecular ion plus two, [M + 2] peak. The relative heights of these two peaks are proportional to the isotopic abundance ratios of the halide. For example, 2‐chloropropane and 1‐bromopropane display two peaks with relative peak heights in a 3:1 and...
1.5K


![The Synthesis of [Sn10SiSiMe334]2- Using a Metastable SnI Halide Solution Synthesized via a Co-condensation Technique](/_next/image?url=https%3A%2F%2Fcloudfront.jove.com%2FCDNSource%2Fteasers%2F54498.jpg&w=3840&q=50)