催化化N-异质与醇的化:直接访问CF3-嵌入的烯
Shuvojit Haldar1, Atanu Bera1, Adrija Ghosh1
1Laboratory of Catalysis and Organic Synthesis, Department of Chemistry, Indian Institute of Technology Roorkee, Roorkee 247667, Uttarakhand, India.
Organic letters
|December 30, 2025
概括
一种新的催化反应从醇和异环环中产生三甲基 (CF3) 嵌入的烯酸. 这种方法可以实现高效的后期功能化,为有机合成提供了有价值的工具.
科学领域:
- 有机化学 有机化学
- 催化剂是一种催化剂.
- 化学 的化学
背景情况:
- 三甲基 (CF3) 嵌入式烯酸是制药和材料科学中宝贵的构建模块.
- 开发有效的CF3-olefins合成方法仍然是有机化学的一个挑战.
研究的目的:
- 报告一种新的顺序催化反应,用于合成CF3嵌入式烯酸.
- 用各种基板来证明开发的协议的广泛适用性.
主要方法:
- 顺序的Ni-催化无受体脱的化醇.
- 与2-oxindoles或甲基N-heteroarenes进行凝结反应.
- 基质范围的探索,包括初级和二级酒精和各种异环.
主要成果:
- 成功合成了超过21个CF3嵌入型烯酸样本,产量高达89%.
- 对广泛的2-oxindoles,甲基azaarenes和醇有被证明的耐受性.
- 实现了维生素衍生物的后期功能化,突出了该方法的实际实用性.
结论:
- 开发的Ni催化序列反应提供了一个高效和多功能途径,以CF3嵌入的烯酸.
- 该协议的耐受性和后期功能化能力使其成为合成有机化学的宝贵补充.
- 进一步的机理学研究正在进行中,以阐明反应途径.
相关概念视频
Halogenation of Alkenes
18.3K
Halogenation is the addition of chlorine or bromine across the double bond in an alkene to yield a vicinal dihalide. The reaction occurs in the presence of inert and non-nucleophilic solvents, such as methylene chloride, chloroform, or carbon tetrachloride.
Consider the bromination of cyclopentene. Molecular bromine is polarized in the proximity of the π electrons of cyclopentene. An electrophilic bromine atom adds across the double bond, forming a cyclic bromonium ion intermediate.
Consider the bromination of cyclopentene. Molecular bromine is polarized in the proximity of the π electrons of cyclopentene. An electrophilic bromine atom adds across the double bond, forming a cyclic bromonium ion intermediate.
18.3K
Electrophilic Aromatic Substitution: Fluorination and Iodination of Benzene
7.3K
Bromination and chlorination of aromatic rings by electrophilic aromatic substitution reactions are easily achieved, but fluorination and iodination are difficult to achieve. Fluorine is so reactive that its reaction with benzene is difficult to control, resulting in poor yields of monofluoroaromatic products. To address this, Selectfluor reagent is used as a fluorine source in which a fluorine atom is bonded to a positively charged nitrogen.
7.3K
Base-Promoted α-Halogenation of Aldehydes and Ketones
4.1K
α-Halogenation of aldehydes and ketones is a reaction involving the substitution of α hydrogens with halogens in the presence of a base. The reaction begins with the abstraction of α hydrogen by the base to produce a nucleophilic enolate ion. This intermediate undergoes a subsequent nucleophilic substitution with the halogen to produce a monohalogenated carbonyl compound. If the starting substrate has more than one α hydrogen, it is difficult to stop the reaction...
4.1K
Radical Substitution: Allylic Bromination
6.4K
In organic synthesis, the formation of products can be altered by changing the reaction conditions. For example, a dibromo addition product is formed when propene is treated with bromine at room temperature. In contrast, propene undergoes allylic substitution in non-polar solvents at high temperatures to give 3-bromopropene. In order to avoid the addition reaction, the bromine concentration must be kept as low as possible throughout the reaction. This can be achieved using N-bromosuccinimide...
6.4K
Reduction of Alkynes to cis-Alkenes: Catalytic Hydrogenation
8.9K
Introduction
Like alkenes, alkynes can be reduced to alkanes in the presence of transition metal catalysts such as Pt, Pd, or Ni. The reaction involves two sequential syn additions of hydrogen via a cis-alkene intermediate.
Like alkenes, alkynes can be reduced to alkanes in the presence of transition metal catalysts such as Pt, Pd, or Ni. The reaction involves two sequential syn additions of hydrogen via a cis-alkene intermediate.
8.9K
Acid-Catalyzed α-Halogenation of Aldehydes and Ketones
4.7K
By replacing an α-hydrogen with a halogen, acid-catalyzed α-halogenation of aldehydes or ketones yields a monohalogenated product
In the first step of the mechanism, the acid protonates the carbonyl oxygen resulting in a resonance-stabilized cation, which subsequently loses an α-hydrogen to form an enol tautomer. The C=C bond in an enol is highly nucleophilic because of the electron-donating nature of the –OH group. Consequently, the double bond attacks an electrophilic halogen to form a...
In the first step of the mechanism, the acid protonates the carbonyl oxygen resulting in a resonance-stabilized cation, which subsequently loses an α-hydrogen to form an enol tautomer. The C=C bond in an enol is highly nucleophilic because of the electron-donating nature of the –OH group. Consequently, the double bond attacks an electrophilic halogen to form a...
4.7K


